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3 years ago

Please helppppp Consider the function f whose graph is shown above

Mathematics

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:

It is C. Just look at the farthest points, and those are the numbers in your inequality.

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Mr. Saba owns two food trucks. He rents two spots at the state fair. This table shows the number of tacos the two food trucks so

Nadya [2.5K]

Using the data for each truck lets calculate,

median for truck 1 - 511.5
median for truck 2 - 650.5

lets consider each statement
A.medians for both trucks are the same - wrong
median for 1 and 2 are 511.5 and 650.5 respectively

B. the two trucks sold most number of tacos on 3rd day
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong

C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct

D.
total number of tacos for each truck -
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong

5 0

3 years ago

Read 2 more answers

Can you plz help me with this, because I don’t know how to do this and can u plz explain how to do it

Alecsey [184]

Answer:

Step-by-step explanation:

You can start this in may ways but let's start by isolating one of the parenthesis:

x (x² - 5) = - (x - 3)

x³ - 5x = -x + 3 (here I multiplied x for what's inside the parenthesis and the "minus" signal by the other parenthesis which was (x - 3))

x³ - 5x + x = 3

x³ -4x = 3

x³ -4x -3 = 0 (now this right here is a "depressed cubic equation" and it's one of the toughest sit of all time, so good luck with that, you might wanna take a look at this:

ytb/watch?v=rNDy2ZFvG1E

or maybe I'm doing something wrong and it's simpler than that, but whaterver...)

4 0

3 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

3 0

2 years ago

Help me graph it please

VikaD [51]

Here's a rough graph haha
the graph has a factor of 4/1 (considered the "slope"), and the vertex is translated 2 units to the right (whatever is in the | lines | has the negative/positive flipped), and 6 units down.

8 0

3 years ago

Will mark BRAINLIEST to correct answer! Please help, this has to be correct. Thanks!

pogonyaev

The answer would be 314.16 square cm
Hope this helps! :)

4 0

4 years ago

Read 2 more answers