Answer: c(x) = $50*x + $24
Step-by-step explanation:
First, this situation can be modeled with a linear equation like:
c(x) = s*x + b
where c is the cost, s is the slope, x is the number of cubic yards of mulch bought, and b is the y-intercept ( a constant that no depends on the number x)
Then we know that:
The company charges $50 per cubic yard, so the slope is $50
A delivery charge of $24, this delivery charge does not depend on x, so this is the y-intercept.
Then our equation is:
c(x) = $50*x + $24
This is:
"The cost of buying x cubic yards of mulch"
There is 24 avocados in each crate
Divide 8640 and 360 to get 24
Hope this will help you!
Answer:
y = 0
Step-by-step explanation:
It is always a good idea to look at the question and make some observations about it. Here, you might observe ...
- all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
- y is a factor of every exponent
The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.
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To solve the equation, you can write it in terms of powers of 3.
(3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)
3^(-5y) = 3^(-15y)·3^(-4y)
3^(-5y) = 3^(-19y)
-5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3
14y = 0 . . . . . . . . . . add 19y
y = 0 . . . . . . . . . . . one solution
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The rules of exponents we used are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
Step-by-step explanation:
4. To use SSS, you need three pairs of congruent sides. You're given two pairs of congruent sides, so the additional information needed is WY ≅ KM.
5. To use ASA, you need a pair of congruent sides between two pairs of congruent angles. You're given one pair of congruent angles, and since the triangles share a common side, we know BC ≅ BC. So the additional information needed is ∠WBC ≅ ∠ACB.
6. To use SAS, you need a pair of congruent angles between two pairs of congruent sides. You're given two pairs of congruent sides, so the additional information needed is ∠I ≅ ∠F.
Translating a graph upwards just means adding or subtracting a value from the initial function.
So to push a graph up, you just add (+) the number of units onto the original function.
