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2 years ago

DOES THE GRAPH OF THE STRAIGHT LINE WITH SLOPE OF 4 AND Y-INTERCEPT OF -3 PASS THROUGH THE POINT (-2, 9)

Mathematics

2 answers:

lisov135 [29]2 years ago

6 0

Equation of the given line will be :

y = 4x - 3

now, let's plug the value of x as the x - coordinate of the above point (-2 , 9) to check whether it lies on the line or not.

$y = 4( - 2) - 3$

$y = - 8 - 3$

$y = - 11$

now, since value of isn't equal to the y - coordinate of the given point, so the point doesn't lies on the line.

Artist 52 [7]2 years ago

4 0

Answer:

Equation of the given line will be :

y = 4x - 3

now, let's plug the value of x as the x - coordinate of the above point (-2 , 9) to check whether it lies on the line or not.

y = 4( - 2) - 3y=4(−2)−3

y = - 8 - 3y=−8−3

y = - 11y=−11

now, since value of isn't equal to the y - coordinate of the given point, so the point doesn't lies on the line.

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Answer:

2 10/16 or 2 5/8

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2+10/16=2 10/16 or 2 5/8.

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3 years ago

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Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

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3 years ago

A shirt is originally priced at $24.50 a shirt goes on sale for 30% off the original price how much money to the nearest cent do

Ainat [17]

Answer:

7.86 is the answer

Step-by-step explanation:

30% of 24.50 is 7.35.

7.35+ 7% is 7.86

7.86 to the nearest cent is 7.86

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