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Brrunno [24]
4 years ago
15

Maricela heard that as a general rule, she should spend no more than one week's pay on rent. If Maricela's salary is $48,000 per

year, what is the maximum amount per month that she should spend on rent?
Mathematics
2 answers:
Anna [14]4 years ago
8 0
You just need to divide the yearly salary by the number of weeks per year to get 48000/52 weeks=923 is the amount that she should spend no more than one week's pay which is the maximum amount per month that she can spend on rent.
kipiarov [429]4 years ago
6 0

Answer:

$923 apex

Step-by-step explanation:

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Logs are stacked in a pile. The bottom row has 50 logs and next to bottom row has 49 logs. Each row has one less log than the ro
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Answer:

46 logs on the 5th row.

Step-by-step explanation:

Number of logs on the nth row is

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A. 6x^3+18x<br> b.6x^2+3<br> c.36x^2+18<br> d. 36x^2+3
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<u><em>The answer:</em></u> 6x^3+18x

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What's the radius of a circle with an area of 64 square feet?
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Read 2 more answers
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

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Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

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Read more about parabola at:

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