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lapo4ka [179]
3 years ago
13

The area of the right triangle shown is 24 square feet.

Mathematics
2 answers:
Yakvenalex [24]3 years ago
5 0

Answer: a b d on edge

Step-by-step explanation: no cap

Goryan [66]3 years ago
4 0

<em><u>The equations used to find the length of leg of triangle are:</u></em>

0.5x(x+2) = 24\\\\x^2+2x-48=0\\\\x^2+(x+2)^2 = 100

<em><u>Solution:</u></em>

From given,

Area of right triangle = 24 square feet

Also from given figure in question (attached below )

base = x and height = x + 2

<em><u>The area of triangle is given by formula:</u></em>

Area = \frac{1}{2} \times base \times height

Substituting the values we get,

24 = \frac{1}{2} \times x \times (x+2)\\\\24 = 0.5x(x + 2)\\\\48 = x(x+2)\\\\x^2 + 2x - 48 = 0\\\\

<em><u>Also, the above equation can be written as,</u></em>

x^2 + (x+2)^2 =100

<em><u>Thus the equations used to find the length of leg of triangle are:</u></em>

0.5x(x+2) = 24\\\\x^2+2x-48=0\\\\x^2+(x+2)^2 = 100

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2 years ago
The area of a rectangle is<br> 3/8 in and the length is 5/8 What is the width?
liberstina [14]

Answer:

The width W is :

W=\frac{3}{5}

Step-by-step explanation:

<em>Let A be the area of the rectangle </em>

<em>Let L be the length of the rectangle</em>

<em>Let W be the width of the rectangle </em>

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Formula:

A = L × W

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\begin{aligned}A &=L \times W \\\Rightarrow W &=\frac{A}{L} \\\Rightarrow W &=\frac{\frac{3}{8}}{\frac{5}{8}} \\&=\frac{3}{8} \times \frac{8}{5} \\&=\frac{3 \times 8}{8 \times 5} \\&=\frac{3}{5}\end{aligned}

6 0
3 years ago
Which table represents la linear function?
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Answer:

I believe it would be the last table.

Step-by-step explanation:

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3 years ago
The radius of a circle is 7cm. Find the circumference of the circle. Use 22/7 for pi
finlep [7]

Answer:

Hi I'm learning the same thing and I just got it I think it's C=43.98cm

8 0
3 years ago
The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0
3 years ago
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