Answer: The final temperature is 470K
Explanation: Using the relation;
Q= ΔU +W
Given, n = 2mol
Initial temperature T1= 345K
Heat =Q= 2250J
Workdone=W=-870J(work is done on gas)
T2 =Final temperature =?
ΔU =3/2nR(T2-T1)
ΔU=3/2 × 2 ×8.314 (T2 - 345)
ΔU=24.942(T2-345)
Therefore Q = 24.942(T2-345)+ (-870)
2250=24.942(T2-345)+ (-870)
125.09=(T2-345)
T2 =470K
Therfore the final temperature is 470K
Answer: It would be 12 m/s.
Explanation: It would be this because If you go from rest to sprint it would be 12 m/s. Also, I did this the other day.
Answer:
1469 miles /3.25 hours = 452 miles per hours
Explanation:
divide distance by the time it takes to get there
For an automobile spring using a 25 kg car battery, the spring constant is mathematically given as
K=4.08.3N/m
<h3>What is the spring constant?</h3>
Question Parameter(s):
a 25 kg car battery
The springs are pulled out by 0.06 meters
Generally, the equation for the Force is mathematically given as
F=mg
Therefore
F=(25*9.8)
(25*9.8)=K(0.06)
K=4.08.3N/m
In conclusion, the spring constant
K=4.08.3N/m
Read more about Force
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