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Ivahew [28]
2 years ago
13

State the career function of computer engineering​

Physics
2 answers:
Crank2 years ago
6 0

Answer:

Computer engineer duties include doing research on software and computer hardware. Designing and testing computer hardware components. Like  processors, circuit boards, memory devices and routers. Writing and testing software mobile devices and computers.

Explanation:

Murljashka [212]2 years ago
3 0

Answer:

Computer engineer duties include: Conducting research on software and computer hardware. Designing and testing computer hardware components, such as processors, circuit boards, memory devices and routers. Writing and testing software for mobile devices and computers.

Explanation:

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A hiker travels south along a straight line path for 1.5 hours with an average velocity of 0.75 km/hr, then travels south for 2.
ANTONII [103]
Distance travelled in south direction= 1.5hr*0.75km/hr= 1.125km
Distance travlled in north direction= 0.90*2.5=2.25
Net displacement = 2.25-1.125= 1.125 to the north
7 0
3 years ago
A motorcyclist who is moving along an x axis directed toward the east has an acceleration given by a = (6.30 - 2.20t) m/s2 for 0
musickatia [10]
<span>(a) 12.02 m/s
 (b) 52.2 meters

   This problem is an example of integral calculus. You've been given an acceleration vector which is usually known as the 2nd derivative. From that you need to calculate the velocity function (1st derivative) and position (actual function) by successively calculating the anti-derivative. So:
   A(t) = 6.30 - 2.20t
 V(t) = 6.30t - 1.10t^2 + C

   We now have a velocity function, but need to determine C. Since we've been given the velocity at t = 0, that's fairly trivial.
 V(t) = 6.30t - 1.10t^2 + C
 3 = 6.30*0 - 1.10*0^2 + C
 3 = 0 + 0 + C
 3 = C

    So the entire velocity function is:
 V(t) = 6.30t - 1.10t^2 + 3
 V(t) = -1.10t^2 + 6.30t + 3

   Now for the location function which is the anti-derivative of the velocity function.
  V(t) = -1.10t^2 + 6.30t + 3
  L(t) = -0.366666667t^3 + 3.15t^2 + 3t + C

   Now we need to calculate C. And once again, we've been given the location for t = 0, so
 L(t) = -0.366666667t^3 + 3.15t^2 + 3t + C
 7.3 = -0.366666667*0^3 + 3.15*0^2 + 3*0 + C
 7.3 = 0 + 0 + 0 + C
 7.3 = C

   L(t) = -0.366666667t^3 + 3.15t^2 + 3t + 7.3

   Now that we have the functions, they are:
 A(t) = 6.30 - 2.20t
 V(t) = -1.10t^2 + 6.30t + 3
 L(t) = -0.366666667t^3 + 3.15t^2 + 3t + 7.3

    let's answer the questions.
 (a) What is the maximum speed achieved by the cyclist?
 This can only happen at those points that meet either of the following criteria.
  1. The derivative is undefined for the point.
  2. The value of the derivative is 0 for the point.
 As it turns out, the 1st derivative of the velocity function is the acceleration function which we have. So
 A(t) = 6.30 - 2.20t
 0 = 6.30 - 2.20t
  2.20t = 6.30
 t = 2.863636364

   So one of V(0), V(2.863636364), or V(6) will be the maximum value. Therefore: V(0) = 3
 V(2.863636364) = 12.0204545454545
 V(6) = 1.2

   So the maximum speed achieved is 12.02 m/s

   (b) Total distance traveled?
 L(0) = 7.3
 L(6) = 59.5
 Distance traveled = 59.5 m - 7.3 m = 52.2 meters</span>
7 0
3 years ago
What is the Potential energy of a magnetic generator
sergiy2304 [10]

Well potential energy is energy possessed by an object of by the position it's in. For example when you hold back a bow and arrow, but before you shoot it you are containing energy by holding the arrow back. So when you start the magnetic generator (pull or turn to start it) before using it for its purpose that is potential energy. I hope this helps.

8 0
4 years ago
A spaceship from a friendly, extragalactic planet flies toward Earth at 0.201 times the speed of light and shines a powerful las
bagirrra123 [75]

Answer:

The wavelength of observed light on earth is 568.5 nm

Explanation:

Given that,

Velocity of spaceship v= 0.201c

Wavelength of laser \lambda= 697\ nm

We need to calculate the wavelength of observed light on earth

Using formula of wavelength

\lambda_{0}=\lambda_{e}\times\sqrt{\dfrac{1-\dfrac{v}{c}}{1+\dfrac{v}{c}}}

\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-\dfrac{0.201 c}{c}}{1+\dfrac{0.201c}{c}}}

\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-0.201}{1+0.201}}

\lambda=5.685\times10^{-7}\ m

\lambda=568.5\times10^{-9}\ m

\lambda=568.5\ nm

Hence, The wavelength of observed light on earth is 568.5 nm

8 0
3 years ago
A motorcyclist traveling 35 mph slows at he approaches a stos sign. This is an example of..
sergeinik [125]
The correct answer is B. Velocity
7 0
3 years ago
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