when we find the distance we will add all the blocks so
distance = 6+6+4
distance = 14blocks
when we find the displacement we will add and minus too
As you can read he goes to the south 6 and to north 6 so he leave that place and back to the place again so the displacement is 0. and again he goes to the west 4 blocks so the displacement = <em><u>4blocks</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>west</u></em>
<h2>Answer: free electrons</h2>
<u>Plasma</u> is known as the 4th state of matter and is itself ionized gas. In this sense, ionization consists of the production of ions, which are <u>electrically charged atoms or molecules due to</u><u> the excess or lack of electrons</u><u> with respect to a neutral atom or molecule.
</u>
That is why in this process there are always<u> free electrons</u>. Therefore in heating gas to create plasma can yield free electrons, and the correct option is D.
Answer:
<h2>32m/s^2</h2>
Explanation:
We want to find the acceleration based on the given data
Given
distance s=400m
time t= 5s
u= 0m/s since it started from rest
We apply the following expression
s=ut+1/2at^2
substituting we have
400=0*5+1/2*a(5)^2
400=25a/2
cross multiply
25a=400*2
25a=800
divide both sides by 25 we have
a=800/25
a=32m/s^2
The acceleration is 32m/s^2
The answer to your question is C. <span> the Sun's strong gravitational field . This is correct because i took the test :D</span>
Answer:
82780.42123 m/s
14.45 days
Explanation:
m = Mass of the planet
M = Mass of the star = 
r = Radius of orbit of planet = 
v = Orbital speed
The kinetic and potential energy balance is given by

The orbital speed of the star is 82780.42123 m/s
The orbital period is given by
The orbital period is 14.45 days