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Anastaziya [24]
3 years ago
10

Factorise 8f^2 + 7f plz help! answer will get brainliest!!!

Mathematics
2 answers:
Aneli [31]3 years ago
8 0

Answer:

f(8f + 7)

Step-by-step explanation:

8f^2 + 7f

= f(8f + 7)

emmainna [20.7K]3 years ago
3 0
(8+7)
This might be the answer your looking for.
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(4m^5)^3 simplified
vampirchik [111]

Answer:

64m^15

Step-by-step explanation:

im pretty sure this is the answer hope i helped!

3 0
3 years ago
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Akira is folding a piece of paper that is 0.2 millimeters thick in half. The thickness of the paper doubles with each fold. Let
Ostrovityanka [42]

Answer:

t(n)= 0.2 * 2ⁿ

Step-by-step explanation:

Thickness= 0.2 millimeters

paper = 1

n= number of folds

The exponential function will be given by

t(n)= 0.2 * 2ⁿ

so if there's a single fold

t(1)= 0.2 * 2¹

t(1)= 0.4 mm

Now for 2 folds the thickness will be

t(2) = 0.2 *2 ²

t(2)= 0.2 *4

t(2) = 0.8mm

The exponential that represents this scenario is

t(n)= 0.2 * 2ⁿ

And for 3 folds the thickness will be

t(3) = 0.2 *2 ³

t(3)= 0.2 *8

t(3) = 1.6 mm

4 0
3 years ago
What is the area of the figure? Explain.
Dominik [7]

Answer:

  24 cm²

Step-by-step explanation:

The rectangular section on the right is 8 - 4 = 4 cm wide.

It is 3 + 1.5 = 4.5 cm tall.

The area of the rectangular section is ...

  A = LW

  A = (4.5 cm)(4 cm) = 18 cm²

__

The triangular section on the left is 4 cm wide and 3 cm high. Its area is ...

  A = 1/2bh

  A = 1/2(4 cm)(3 cm) = 6 cm²

The total shaded area is the sum of the areas of the triangular section and the rectangular section:

  area = 18 cm² +6 cm² = 24 cm² . . . area of the figure

7 0
3 years ago
54. Find <img src="https://tex.z-dn.net/?f=y%5E%7B%5Cprime%7D" id="TexFormula1" title="y^{\prime}" alt="y^{\prime}" align="absmi
Stella [2.4K]

Step-by-step explanation:

Take the natural log of both sides:

ln ({x}^{y} ) = ln ({y}^{x} )

Logarithm rules allow you to bring down the exponents:

yln(x) = xln(y)

Now differentiate. We will have to implicitly differentiate 'y' since it is a function of 'x'. Both sides require the product rule:

\frac{dy}{dx} ln(x) +  \frac{y}{x}  = ln(y) +  \frac{x}{y}  \frac{dy}{dx}

Isolate the terms that have y' since that is what we want:

\frac{dy}{dx} ln(x) -  \frac{x}{y}  \frac{dy}{dx}= ln(y) - \frac{y}{x}

Factor out y' to get:

\frac{dy}{dx}( ln(x) -   \frac{x}{y})= ln(y) - \frac{y}{x}

Therefore:

\frac{dy}{dx} =  \frac{ln(y) -  \frac{y}{x} }{ln(x) -  \frac{x}{y} }

7 0
2 years ago
I need help with this one
Rudik [331]

Answer:

8

Step-by-step explanation:

Just divide and plug it into the formula. YOu then get the answer

4 0
3 years ago
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