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ANTONII [103]
3 years ago
6

%7D%7B%5Csqrt%7Ba%2Bb%7D%20%7D" id="TexFormula1" title="\frac{\sqrt{a+b} }{\sqrt{a-b} } +\frac{\sqrt{a-b} }{\sqrt{a+b} }" alt="\frac{\sqrt{a+b} }{\sqrt{a-b} } +\frac{\sqrt{a-b} }{\sqrt{a+b} }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Tpy6a [65]3 years ago
4 0

Step-by-step explanation:

\frac{ \sqrt{a + b} }{ \sqrt{a - b} }   +   \frac{ \sqrt{a - b} }{ \sqrt{a + b} }  \\ squaring \: on \: both \: sides \\   \frac{a + b}{a - b}  +  \frac{a - b}{a + b}  \\  \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)}  \\   \frac{ {(a + b)}^{2} +  {(a - b)}^{2}  }{ {a}^{2} -  {b}^{2}  }  \\  remaining \: in \: attachment

thank \: you

andrezito [222]3 years ago
3 0

Answer:

\frac{(a+b)}{a^{2} -b^{2}  } + \frac{(a-b)}{a^{2} -b^{2}  } = \frac{2a}{a^{2} -b^{2}  }

Step-by-step explanation:

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Globalization leads to more trade between countries
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Read 2 more answers
Smith cut his peanut butter
Lorico [155]
The answer is the square root of 101.75
Assuming that the sandwich Is a square, after cutting it diagonally, it turns into 2 triangles. To look for a missing length of a triangle, you use Pythagorean’s theorem a^2+b^2=c^2
Since c is 12 and a is 6.5 you just square 12 and square 6.5
144 42.25
Subtract it
101.75
You then have to find the square root of it. You can leave it as it is as √101.75 or just solve for it and round it to 10.09
3 0
3 years ago
Sophia finished 2/3 of a book. She calculated that she finished 90 more pages than she has yet to read. How long is her book?
TEA [102]

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6 0
3 years ago
Use the table below. Do x and y have a proportional relationship? Explain.
nydimaria [60]

Answer:

No

Step-by-step explanation:

For x and y to have a proportional relationship, then

the ratio of k = \frac{y}{x} must be equal for all points

(2, 5) → k = \frac{5}{2} = 2.5

(3, 7.5) → k = \frac{7.5}{3} = 2.5

(5, 12.5) → k = \frac{12.5}{5} = 2.5

(18, 8) → k = \frac{18}{8} = 2.25 ≠ 2.5

k is not equal for all values , hence no proportional relationship exists

8 0
3 years ago
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