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ANTONII [103]
3 years ago
6

%7D%7B%5Csqrt%7Ba%2Bb%7D%20%7D" id="TexFormula1" title="\frac{\sqrt{a+b} }{\sqrt{a-b} } +\frac{\sqrt{a-b} }{\sqrt{a+b} }" alt="\frac{\sqrt{a+b} }{\sqrt{a-b} } +\frac{\sqrt{a-b} }{\sqrt{a+b} }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Tpy6a [65]3 years ago
4 0

Step-by-step explanation:

\frac{ \sqrt{a + b} }{ \sqrt{a - b} }   +   \frac{ \sqrt{a - b} }{ \sqrt{a + b} }  \\ squaring \: on \: both \: sides \\   \frac{a + b}{a - b}  +  \frac{a - b}{a + b}  \\  \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)}  \\   \frac{ {(a + b)}^{2} +  {(a - b)}^{2}  }{ {a}^{2} -  {b}^{2}  }  \\  remaining \: in \: attachment

thank \: you

andrezito [222]3 years ago
3 0

Answer:

\frac{(a+b)}{a^{2} -b^{2}  } + \frac{(a-b)}{a^{2} -b^{2}  } = \frac{2a}{a^{2} -b^{2}  }

Step-by-step explanation:

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Write an equation in slope-intercept form for the line that satisfies the following condition.passes through (20, 1), parallel t
Dmitrij [34]

Slope-intercept form:  y = mx + b  

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they have to have the same slope.

y = 6x + 6    The slope of this line is 6, so the parallel line's slope is also 6.

Now that you know m = 6, substitute/plug it into the equation:

y = mx + b         Plug in 6 for "m" in the equation  

y = 6x + b     To find "b", plug in the point (20, 1) into the equation

1 = 6(20) + b

1 = 120 + b       Subtract 120 on both sides to get "b" by itself

1 - 120 = 120 - 120 + b

-119 = b         Now that you know b = -119, plug it into the equation

y = 6x - 119

5 0
4 years ago
Which could be used to evaluate the expression -6(4 2/3)
olasank [31]

Answer:

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Step-by-step explanation:

4 2/3=14/3

-6(14/3)=-2*14=-28

6 0
3 years ago
SOLVE. |y - z| when y=7, z= 11
tia_tia [17]

Answer:

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8 0
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no time chuck a whole $50 bill at the employee

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3 years ago
Two airplanes are are 1600 miles apart and heading toward each other at different altitudes. The first plane is traveling north
Elden [556K]

The planes will pass each other in 1.14 hours.

Why?

To solve the problem, we must remember that since both planes are heading toward each other, the speed to the calculations will be their combined speeds.

The speed will be:

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Now, calculating the time, we have:

x=v*t\\\\1600mi=1400mph*t\\\\t=\frac{1600mi}{1400mph}=1.14hours

Hence, the planes will pass each other in 1.14 hours.

Have a nice day!

6 0
3 years ago
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