Hello!
This is a problem about probability.
What we would first do is find the theoretical probability that Susan would roll the number 3 on a die.
Assuming that this is a fair six sided die, there is only one face with the number 3, and there are 6 sides, meaning that the probability that Susan rolls a 3 would be
.
Now, Susan is rolling a die 1,086, meaning that we can divide this number by 6 to find the theoretical number of times that Susan would roll the number 3 on this die.
You should get 181 times, which would be a good estimate of how many times she could roll the number 3.
Hope this helps!
Answer:
The answer to your question is below
Step-by-step explanation:
Inequality 1
7(x + 2) - 8 ≥ 13
7x + 14 - 8 ≥ 13
7x + 6 ≥ 13
7x ≥ 13 - 6
7x ≥ 7
x ≥ 7/7
x ≥ 1
Inequality 2
8x - 3 < 4x - 3
8x - 4x < - 3 + 3
4x < 0
x < 0 / 4
x < 0
Interval notation (-∞ , 0) U [1, ∞)
See the graph below
The answer to this question is B) 0
The six sided die has 6 sides (with numbers 1,2,3,4,5 and 6). That's why the probability to roll number 2 in one trial is equal to

.If you'll dol 50 trials, then you can expect

times to roll number 2 (8 or 9 times).