Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
c
Explanation:
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The time difference between the occurrences of two peaks is the period of the wave. The time difference between two consecutive black dots marked also gives the period of the wave. Generally, symbol ‘T’ is used to denote period in physics. Unit of measuring period is seconds (s).
Answer: The following which is not true is letter A.
Explanation: Because microtubules require GTP hydrolysis. The process requires energy from GTP hydrolysis. It occurs at the beta- tubulin subunit after incorporation of the tubulin dimer into the microtubule lattice.
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