Answer:
Step-by-step explanation:
Let the first term is a and common difference is d.
<u>The nth term is:</u>
<u>We have:</u>
<u>The difference of these terms is:</u>
- (a + 8d) - (a + 5d) = 16 - 15
- 3d = 1
- d = 1/3
<u>Then the first term is:</u>
- a + 5*1/3 = 15
- a = 15 - 5/3 = 13 1/3
<u>The nth term equation is:</u>
- aₙ = 13 1/3 + 1/3(n - 1) = 1/3n + 13
<u>If the nth term is 22, find n:</u>
- 1/3n + 13 = 22
- 1/3n = 22 - 13
- 1/3n = 9
- n = 9*3
- n = 27
Y=2x or y=x+2 If you plug in the ordered pairs for both, they fit.
Answer:
60cm^2
Step-by-step explanation:
We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...
K = sr
where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.
K = (12 cm) (5cm) = 60 cm²
_____
A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.
I think it's A because 35n is independent from the 50.
The top one shows they are parallel lines because it shows angles of both lines and the transversal
