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2 years ago

PLEASE HELPP MEEE!!!!!

Mathematics

1 answer:

ale4655 [162]2 years ago

7 0

Answer:

a little bit of a very nice and smart and k liye kuch bhi nahi ha ha bol rahe hai

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A standard toilet uses 1.6 gallons per flush. If a toilet is flushed five times per day, how much water will be used in a month

djyliett [7]

Answer:

I believe the answer is 48 gallons.

Step-by-step explanation:

Multiply 1.6 by 30 and you get 48

6 0

2 years ago

Read 2 more answers

Angie bought 312 pounds of apples to make a pie. There are 16 ounces in one pound. How many ounces of apples did she buy?

vfiekz [6]

4,992 ounces
multiply 312 by 16

3 0

2 years ago

PLEASE ANSWER THIS IS URGENT

mr Goodwill [35]

Answer:

i think its 48 but dont trust me im just doing this for points hope you get a good grade on it

Step-by-step explanation:

6 0

2 years ago

Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.

borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 14, p = 0.8$

P(x>10)

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501$

$P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501$

$P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539$

$P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440$

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981$

So P(x > 10) = 0.6981.

8 0

2 years ago

Simplify. (−5p4z6u)3

sineoko [7]

The rules of exponents tell you that you can distribute the exponent to each of the factors. When one already has an exponent, those exponents multiply.
$(-5p^{4}z^{6}u)^{3}=(-5)^{3}\cdot(p^{4})^{3}\cdot(z^{6})^{3}\cdot u^{3}\\\\=-125p^{4\cdot 3}z^{6\cdot 3}u^{3}\\\\=-125p^{12}z^{18}u^{3}$

4 0

3 years ago