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Oliga [24]
3 years ago
8

What’s the difference between m=change in y and change in x and m =y2-y1and x2-x1

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

it's the same thing

slope =  \frac{Δy}{Δx} or  \frac{change \: in \: y}{change \: in \: x}  =  \frac{y2 - y1}{x2 - x1}  =  \frac{rise}{run}

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labwork [276]

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When you deposit money in a bank, the bank usually pays you for the use of your money. When you take out a loan from a bank, you have to pay the bank for the use of their money. In both cases, the money paid is called the interest. It is usually expressed as a percent. Here we shall look at a formula for simple interest.

3 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 134 millimeters,
Arisa [49]

; 134

a:8

n:44

3.6

3.6

P,ob.Z);Jlty : 1 - P(:

<z<-

[ - ]]p(-2.98 ' z ' 2.98)]

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6 0
3 years ago
PLS HURRY I NEED THE ANSWER FAST
balandron [24]

Answer:

16

notice how a right triangle was formed, and the Pythagorean theorem could be used to solve this :

a^2 + b^2 = c^2

a^2 + 15^2 = 17^2

a^2 + 225 = 289

a^2 = 64

a= 8

multiply it by 2 to get the side of the base

8 * 2 = 16

5 0
3 years ago
How do you factor 2x^2+x-3
xxMikexx [17]
Find the factors of -3:
1,-3 and 3,-1

which ever adds up to 1 multiplied by 2

the answer is (2x+3)(x-1)

hope this helps
7 0
3 years ago
A pool measuring 10 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the po
igomit [66]

Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.

<h3>How to find the width and length?</h3>

First, find the area of the pool:

= Length x Width

= 10 x 26

= 260 meters ²

The area of the path can therefore be found to be:

= Total area of pool and path combined - Area of pool

= 1,092 - 260

= 832 meters²

Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path

= √832

= 28.8

In conclusion, the width and length of the path are 28.8 meters.

Find out more on combined area at brainly.com/question/12966430

#SPJ1

8 0
1 year ago
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