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Answer:
The number of moles of oxygen present in the crew cabin at any given time is 615.309 moles
Explanation:
The given parameters are;
Volume of the crew cabin = 74,000 L
Pressure of the crew cabin = 1.00 atm
Percentage of nitrogen in the mixture of gases in the cabin = 80%
Percentage of oxygen in the mixture of gases in the cabin = 20%
Temperature of the cabin = 20°C = 293.15 K
Therefore, volume of oxygen in the crew cabin = 20% of 74,000 L
Hence, volume of oxygen in the crew cabin =
From the universal gas equation, we have;
Where:
n = Number of moles of oxygen
P = Pressure = 1.00 atm
V = Volume of oxygen = 14,800 L
T = Temperature = 293.15 K
R = Universal Gas Constant = 0.08205 L·atm/(mol·K)
Plugging in the values, we have;
The number of moles of oxygen present in the crew cabin at any given time = 615.309 moles.
Answer: hello your question is poorly written below is the complete question
answer:
For N1 : sp³ orbital
For N2: p orbital
For N3 : p orbital
For N4 : sp² orbital
For N5 : sp² orbital
Explanation:
Determining the type of orbital in which the lone pair on each N atom will reside.
From the configuration attached below we can determine the type of orbital and they are ;
For N1 : sp³ orbital
For N2: p orbital
For N3 : p orbital
For N4 : sp² orbital
For N5 : sp² orbital
