Is the path of electrons orbital or reactive?

What you all are doing?

earnstyle [38]

Answer:playing

Explanation:

8 0

2 years ago

Read 2 more answers

The half-life of Erbium-165 is 10.4 hours. After 24 hours a sample has been reduced to a mass of 2 mg. What was the initial mass

Pachacha [2.7K]

Answer:

$[A_0]=10\ mg$

$[A_t]=0.08245\ mg$

Explanation:

Given that:

Half life = 10.4 hours

$t_{1/2}=\frac{\ln2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{10.4}\ hour^{-1}$

The rate constant, k = 0.06664 hour⁻¹

Time = 24 hours

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t = 2 mg

$[A_0]$ is the initial concentration = ?

So,

$2\ mg=[A_0]\times e^{-0.06664\times 24}$

$[A_0]=10\ mg$

Now, time = 3 days = 3*24 hours = 72 hours ( 1 day = 24 hours)

$[A_0]=10\ mg$

Thus,

$[A_t]=10\times e^{-0.06664\times 72}\ mg=0.08245\ mg$

6 0

4 years ago

sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction

prisoha [69]

Answer:

2.76 × 10⁻¹¹

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹: 0 0 -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

$\text{The relationship between $\Delta G^{\circ}$ and K is}\\\Delta G^{\circ} = -RT \ln K$

T = (25.0 + 273.15) K = 298.15 K

$\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}$

3 0

4 years ago

Aluminum (Al) has an atomic number of 13 and an atomic mass of 27. Which of the following correctly shows the electron arrangeme

adell [148]

The correct answer would be (C) 2,8,3

Explanation:
A full first shell is comprised of two electrons, and for the shells in between the max is 8 (for this small of an element, it can be larger for some larger elements; but that’s beside the point), and aluminum is in group 13 so it has 3 valance electrons.

8 0

4 years ago

Given the reaction: Ca + 2H2O → Ca(OH)2 + H2 What is the total number of moles of Ca needed to react completely with 4.0 moles o

DiKsa [7]

<u>Answer:</u> The number of moles of calcium metal required is 2.0 moles.

<u>Explanation:</u>

We are given:

Moles of water reacted = 4.0 moles

The given chemical reaction follows:

$Ca+2H_2O\rightarrow Ca(OH)_2+H_2$