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I am Lyosha [343]

2 years ago

5

What is the relationship between the atomic numbers and ionic radii of the elements in the group 7a

1 answer:

kvv77 [185]2 years ago

7 0

Answer:

The ionic radii increase as the atomic numbers increase.

Explanation:

As we go down a Group, we are adding one more electron shell to the ion.

Each successive shell is bigger than the one before it, so the ionic radius should increase with increasing atomic number.

Here is a table of the ionic radii of the X⁻ ions.

<u>Element </u> <u> Z </u> <u> </u><u>r/pm </u>

F 9 133

Cl 17 181

Br 35 196

I 53 220

At 85 227

However, the relation between r and Z is not linear (see graph).

All we can say is the ionic radius increases as the atomic number increases.

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The solubility of oxygen gas in water at 40 ∘c is 1.0 mmol/l of solution. What is this concentration in units of mole fraction?

juin [17]

The formula for mole fraction is:

$mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}$ -(1)

The solubility of oxygen gas = 1.0 mmol/L (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

$1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol$

So, moles of oxygen = 0.001 mol

For moles of water:

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Since, the density of water is 1.0 g/mL.

$Density = \frac{mass}{volume}$

$Mass = 1.0 g/ml\times 1000 mL = 1000 g$

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Substituting the values in formula (1):

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7 0

2 years ago

balu736 [363]

Explanation:

Given -

An organic compound gives H₂ gas with Na
On treatment with alkaline iodine it gives yellow ppt.
On oxidation with CrO₃/H⁺ forms an aldehyde (C₂H₄O)

To Find -

Name the compound and write the reaction involved

Now,

Let A be the organic compound.

Then,

A + Na → + H₂↑
A + I₂ → CHI₃ (yellow ppt.)
A + CrO₃ + H⁺ → C₂H₄O

Now,

Here we see that compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives aldehyde.

Functional group of aldehyde = —CHO

And It forms only 2 Carbon aldehyde it means, It is Ethanal (CH₃CHO).

Compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives ethanal.

It means,

We know that 1° alcohol on oxidation gives aldehyde.

Here it gives 2 Carbon aldehyde.

It means,

Here 2 Carbon and 1° alcohol is used.

Now,

Its cleared that Compound A is Ethanol.

Reaction Involved -

CH₃CH₂OH + Na → CH₃CH₂O⁻Na⁺ + H₂↑
CH₃CH₂OH + I₂ + OH⁻ → CHI₃↓ + HCOO⁻ + HI + H₂O
CH₃CH₂OH + CrO₃ + H⁺ → CH₃CHO

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