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I am Lyosha [343]
3 years ago
5

What is the relationship between the atomic numbers and ionic radii of the elements in the group 7a

Chemistry
1 answer:
kvv77 [185]3 years ago
7 0

Answer:

The ionic radii increase as the atomic numbers increase.

Explanation:

As we go down a Group, we are adding one more electron shell to the ion.

Each successive shell is bigger than the one before it, so the ionic radius should increase with increasing atomic number.

Here is a table of the ionic radii of the X⁻ ions.

<u>Element </u> <u> Z </u> <u> </u><u>r/pm </u>

     F          9   133

     Cl       17    181

     Br      35   196

     I         53  220

     At      85  227

However, the relation between r and Z is not linear (see graph).

All we can say is the ionic radius increases as the atomic number increases.

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3 years ago
Li + HNO3 &gt; LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
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  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
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How many molecules of ethanol (c2h5oh) (the alcohol in alcoholic beverages) are present in 155 ml of ethanol? the density of eth
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First convert volume to mass:

mass = 0.789 g/mL * 155 mL = 122.295 g

 

Then convert mass to number of moles:

number of moles = 122.295 g * (1 mole / 46 g) = 2.66 moles

 

Using avogadros number, we get the molecules:

<span>number of molecules = 2.66 moles * 6.022 x 10^23 molecules / mole = 1.6 x 10^24 molecules</span>

4 0
3 years ago
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