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mr Goodwill [35]
4 years ago
11

The entropy of a sample of H2O increases as the sample changes from a

Chemistry
2 answers:
Dominik [7]4 years ago
8 0

<u>Answer:</u> The correct answer is option 3.

<u>Explanation:</u>

Entropy is defined as the measure of degree of randomness or uncertainty in a system.

It increases whenever the particles move randomly.

In solid state, the particles are orderly arranged and entropy is minimum. In liquid state, the particles are less orderly arranged than solid and entropy increases. In gaseous state, the particles are randomly arranged and hence, the entropy is maximum in this state.

Therefore, whenever there is conversion of solid to liquid to gas, the entropy will increase.

Hence, the correct answer is option 3.

Marrrta [24]4 years ago
5 0
The entropy is a measurement of disorder degree. The entropy from lower to higher is solid, liquid and gas. So the answer is (3) liquid to a gas as the entropy increases.
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In a particular reaction 6.80g of dinitrogen trioxide gas (N203) was actually produced by
xenn [34]

Answer:

<em />

<em>a) Balanced chemical equation:</em>

<em />

<em>       </em>2N_2(g)+3O_2(g)\longrightarrow 2N_2O_3(g)<em />

<em />

<em>b) Theoretical yield:</em>

  • 27.4 g of N₂O₃

c) % yield:

  • 24.5%

Explanation:

The complete question is:

<em>In a particular reaction 6.80g of dinitrogen trioxide gas (N₂0₃) was actually produced by reacting 8.75g of oxygen gas (O₂) with excess nitrogen gas (N₂)</em>

<em>a) Write a balanced chemical equation for the reaction. Be sure to include physical states in the equation.</em>

<em>b) Calculate the theoretical yield (in grams) of dinitrogen trioxide: Use dimensional analysis</em>

<em>c) Calculate the % yield of the product</em>

<em />

<h2>Solution</h2>

<em />

<em>a) Write a balanced chemical equation for the reaction. Be sure to include physical states in the equation.</em>

<em />

<em>       </em>2N_2(g)+3O_2(g)\longrightarrow 2N_2O_3(g)<em />

<em />

Check the balance:

<em />

Atom     Left-handside    Right-hand side

  N              2×2=4                  2×2=4

  O              3×2=6                  2×3=6

  • Mole ratio: it is the ratio of the coefficients of the balanced equation

        \dfrac{2molN_2O_3}{3molO_2}

<em>b) Calculate the theoretical yield (in grams) of dinitrogen trioxide: Use dimensional analysis</em>

<em />

<u>1. Convert 8.75 g of O₂(g) to number of moles</u>

  • number of moles = mass in grams / molar mass
  • molar mass of O₂ = 15.999g/mol
  • number of moles = 8.75g / 15.999 g/mol = 0.5469 mol O₂

<u />

<u>2. Use dimensional analysis to calculate the maximum number of moles of N₂O₃(g) that can be produced</u>

      \dfrac{2molN_2O_3}{3molO_2} \times 0.5469molO_2=0.3646molN_2O_3

<u>3. Convert to mass in grams</u>

  • mass = number of moles × molar mass
  • molar mass of N₂O3 = 76.01g/mol
  • mass = 0.3646mol × 76.01g/mol = 27.7g N₂O3

<em>c) Calculate the % yield of the product</em>

<em />

Formula:

<em />

  • %yield = (actual yield/theoretical yield)×100

Substitute and compute:

  • % yield = (6.80g/27.7g)×100 = 24.5%

<em />

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Answer:

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