This is an incomplete question, here is a complete question.
Phosphorus trifluoride is formed from its elements.
How many grams of fluorine are needed to react with 6.20 g of phosphorus?
Answer : The mass of needed are, 11.4 grams.
Explanation : Given,
Mass of = 6.20 g
Molar mass of = 124 g/mol
Molar mass of = 38 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 1 mole of react with 6 moles of
So, 0.05 moles of react with
moles of
Now we have to calculate the mass of
Therefore, the mass of needed are, 11.4 grams.