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romanna [79]
3 years ago
12

Solve for x and graph the solution on the number line below.

Mathematics
2 answers:
lawyer [7]3 years ago
5 0

The solution to the system of inequality expression is 1 < x < 10

Inequality expressions are expressions not separated by an equal sign

Given the inequality expressions

- 4x – 2 < -6 and - 4x – 2 > -42

For the inequality - 4x – 2 < -6

- 4x – 2 + 2 < -6 + 2

-4x < -4

x > 1

For the inequality  - 4x – 2 > -42

- 4x – 2 + 2> -42 +2

-4x > -40

x < 10

Combining both inequality solutions:

1 < x < 10

Hence the solution to the system of inequality expression is 1 < x < 10

Representing on the number line we have:

Learn more here: brainly.com/question/6874464

AnnZ [28]3 years ago
5 0

The general solution of the pair of equations:

- 4x – 2 < -6 and - 4x – 2 > -42 is; 1 < x > 10

By solving the first inequality;

  • -4x - 2 < -6

  • -4x < -4

By dividing both sides by -4, we have;

x > 1

Subsequently, by solving the second inequality;

  • - 4x – 2 > -42
  • -4x > -40

By dividing both sides by -4, we have;

x < 10

Therefore, the inequality that satisfies both equations is;

1 < x > 10

The image attached contains the solution on the number line.

Read more:

brainly.com/question/18329661

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katovenus [111]
The complete question in the attached figure

we know that

sin40° = opposite side / hypotenuse
opposite side =AC
hypotenuse = AB-------> 10 in
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sin 40=AC/AB---------> AC=AB*sin 40-------> AC=10*sin 40

the answer is
AC=10*sin 40

5 0
3 years ago
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anzhelika [568]

The function that describes the graph is an exponential function

<h3>How to determine the function type?</h3>

From the graph, we have the following highlights:

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Inga [223]

Step-by-step explanation:

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Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
The questions are in the pic the other answer is 356
Andru [333]
The answer to this question is 356
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3 years ago
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