The excerpt that is from an opera aria by Mozart is; Excerpt A
What is the given Excerpt?
Mozart was an Austrian composer, widely recognized as one of the greatest composers in the history of Western music. Unlike any other composer in musical history, he wrote in all the musical genres of his day and excelled in every one. His taste, his command of form, and his range of expression have made him seem the most universal of all composers; yet, it may also be said that his music was written to accommodate the specific tastes of particular audiences.
Mozart wrote several successful operas, such as The Marriage of Figaro (1786), Don Giovanni (1787), and The Magic Flute (1791). Mozart also composed a number of symphonies and sonatas. His last symphony—the Jupiter Symphony—is perhaps his most famous.
The given excerpt which is seen from an audio listened to online is seen to be Excerpt A.
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Answer:
Answer:
I. The hollow sphere has the greater angular momentum.
Explanation:
Given that the mass and radius of hollow sphere and solid sphere are same. Let the mass and radius of two spheres be m and r respectively. The two spheres are rotating having same angular velocity ω .
Moment of inertia of solid sphere, I₁ =
Moment of inertia of hollow sphere, I₂ =
Since, I₁ and I₂ are not equal. Therefore, the statement iv is wrong.
The relation between angular momentum, moment of inertia and angular velocity is :
L = Iω
Let L₁ and L₂ be the angular momentum of solid sphere and hollow sphere respectively.
L₁ = I₁ω and L₂ = I₂ω
As ω is same for both spheres but I₂ is greater than I₁, hence L₂ is greater than L₁.
Therefore, statement I is correct that the hollow sphere has the greater angular momentum.
Explanation:
Answer: A. addition of all grade points in completed courses divided by the
number of classes completed.
From the balanced equation we have:
3Mg + N2 ............> Mg3N2
we can see that:
3 moles of magnesium react with 2 moles of nitrogen.
This means that:
72 grams of magnesium are required to react with 28 grams of nitrogen.
Therefore, to calculate the amount of Mg needed to react with 10 grams of N2, all you have to do is cross multiplication as follows:
mass of Mg = (10*72) / 28 = 25.714 grams