The strength of the electric field (E) at the position indicated by the dot can be obtained with the formula: E = F/q where;
F = Force exerted per unit and
q = Positive electric charge at that point.
<h3>What is the Strength of an Electric Field?</h3>
The strength of an electric field, E refers to the force exerted per unit positive charge. It is indicated by the formula: E = F/q. Its SI unit is Newton per Coulomb or Volts per Meter (V/M).
Note that the strength of an electric field is strongest where the lines are close and weakest when the lines are further apart.
The complete question is not provided but the above formula can be used in arriving at the answer.
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The only way I would think is that when making a PB&J the jelly and peanut butter are on separate breads showing that division between races. But, when you put the two sides together they are supposed to taste better together than alone which might symbolize that when races come together they are better together than seperate.
Elaborate more please, what’s the question
Hm.... I don't know. Is he an actor or some sort of performer?
The Angle HCA is equal to 52°. This is arrived at using the knowledge of the Total value of Angles in a Triangle and the Total Value of Angles in a Polygon.
<h3>
What other principles were used to arrive at the answer?</h3>
The other principles of mathematics that were used to arrive at the above answer are:
- Total Angles on a straight line;
- Total Angles on a point; and
- Line segments.
<h3>What are the Steps to the Solution? </h3>
Step 1 - Recall that we have been given Angles AHB and BAH to be 128° and 28° respectively.
We also know that:
- The sum of angles in a triangle is 180°;...................A
- The sum of angles on a straight line is 180°;.........B
- The sum of angles in a polygon is 360°; while.....C
- The total sum of angles at a point is 360°.............D
Since A...therefore:
When ∠AHB (128°) and ∠BAH are taken from 180° we have DBA = ∠28°.
By observation, we can deduce that ∠BDE, ∠CDH, ∠CEH and ∠AEH are all right-angled triangles.
Using the above, we are able to repeat this process of solving for each angle until we have ∠HCA.
To verify that our answer is correct, recall that sum of angles in a polygon is 360°
That means:
∠BDA + ∠DHE + ∠CEH + ∠HCA = 360°
That is, 90+ 128 + 90 + 52 = 360°
See attached images and;
Learn more about Angles in a Triangle at:
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