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Virty [35]
3 years ago
14

A function includes ordered pairs (−2, 3), (0, −1), (1, 0), (3, 8), and (5, 24). Which point could not be the part of this funct

ion?
Mathematics
1 answer:
madreJ [45]3 years ago
3 0

A relation or an ordered pair may or may not be a function.

An ordered pair will only be a function when the x and y values are unique

<em>The options are not given, so I will provide a general explanation</em>

For an ordered pair to be a function, all the y values must point to different x values.

Take for instance, the given ordered pair

\mathbf{(-2, 3), (0, -1), (1, 0), (3, 8),  (5, 24)}

The above represents a function, because the y-values have different x-values

However, the following ordered pair is not a function

\mathbf{(-2, 3), (0, -1), (1, 0), (3, 8), (3, 9),  (5, 24)}

The reason is that:

y-values 9 and 8 have the same x-value (3)

Read more about ordered pairs and functions at:

brainly.com/question/11482687

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Answer:

The minimum number of cities we need to contact is 96.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

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The margin of error is:

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So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

In this problem, we have that:

p = 0.5, M = 0.1

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 1.96*\sqrt{\frac{0.5*0.5}{n}}

0.1\sqrt{n} = 0.98

\sqrt{n} = 9.8

(\sqrt{n})^{2} = (9.8)^{2}

n = 96

The minimum number of cities we need to contact is 96.

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