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Virty [35]
3 years ago
14

A function includes ordered pairs (−2, 3), (0, −1), (1, 0), (3, 8), and (5, 24). Which point could not be the part of this funct

ion?
Mathematics
1 answer:
madreJ [45]3 years ago
3 0

A relation or an ordered pair may or may not be a function.

An ordered pair will only be a function when the x and y values are unique

<em>The options are not given, so I will provide a general explanation</em>

For an ordered pair to be a function, all the y values must point to different x values.

Take for instance, the given ordered pair

\mathbf{(-2, 3), (0, -1), (1, 0), (3, 8),  (5, 24)}

The above represents a function, because the y-values have different x-values

However, the following ordered pair is not a function

\mathbf{(-2, 3), (0, -1), (1, 0), (3, 8), (3, 9),  (5, 24)}

The reason is that:

y-values 9 and 8 have the same x-value (3)

Read more about ordered pairs and functions at:

brainly.com/question/11482687

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Answer:

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Step-by-step explanation:

first, we need to find the GCF (Greatest Common Factor) which is the highest number that can go into every number in the equation (In this case, those numbers are 24 and 30)

The GCF for this would be 6, meaning that there would be 6 bags with and equal amount of granola bars and protein bars.
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Step-by-step explanation:

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hope it helps you!!!

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