Answer:
The length of side is 42.4 inches.
Step-by-step explanation:
Given that:
Diagonal of square = 60 inches
As all sides of a square are equal, thus
Side of square = x
The diagonal will be the hypotenuse of a right angled triangle.
Using Pythagorean theorem;
![x^2+x^2=(60)^2\\2x^2=3600\\x^2=\frac{3600}{2}\\x^2=1800](https://tex.z-dn.net/?f=x%5E2%2Bx%5E2%3D%2860%29%5E2%5C%5C2x%5E2%3D3600%5C%5Cx%5E2%3D%5Cfrac%7B3600%7D%7B2%7D%5C%5Cx%5E2%3D1800)
Taking square root on both sides
![\sqrt{x^2}=\sqrt{1800}\\x=42.4](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%7D%3D%5Csqrt%7B1800%7D%5C%5Cx%3D42.4)
Hence,
The length of side is 42.4 inches.
First isolate 10x^2
10x^2 = 36y^2 + 100
Divide both sides by 10
x^2 = 3.6y^2 + 10
Answer:
I'm not sure what the answer is, but try Photo math. it helps me so much with my equations, and it'll even tell you the steps to get the answer.
Simplify your work by factoring before multiplying. We get:
4(3f-4) 5
---------- * -----------------
16 (3f-4)(3f+4)
Cancel the (3f-4) terms, obtaining:
20
------------------
16 (3f+4)
5
Reducing, we get ------------- and this is the desired result.
4(3f+4)
I think first 80 and second 90