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gtnhenbr [62]
3 years ago
8

Please answer ( DO NOT GIVE A FILE I WILL REPORT ) . Giving brainliest.

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

Explanation:

so its referring to perimeter.

you add all values together.

 this would equal 34.995 .

so, its 34.995 meters of fencing.

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Decide whether each table could represent a proportional relationship. If the
Ymorist [56]

Answer:

Step-by-step explanation:

If given tables in the picture show the proportional relationship,

Number of wheels (w) ∝ Number of buses (b)

w ∝ b

w = kb

Here, k = proportionality constant

k = \frac{w}{b}

Number of buses (b)           Number wheels (w)             Wheels per bus (\frac{w}{b})

          5                                           30                               \frac{30}{5}=6              

          8                                           48                               \frac{48}{8}=6

         10                                           60                               \frac{60}{10}=6

         15                                           90                               \frac{90}{15}=6

Here, proportionality constant is 6.

Similarly, If number of wheels (w) ∝ Number of train cars (t)

w = kt

Here, k = proportionality constant

k = \frac{w}{t}

Number of train cars(t)          Number of wheels(w)     Wheels per train car (\frac{w}{t})

              20                                        184                           \frac{184}{20}=9.2

              30                                        264                           \frac{264}{30}=8.8

              40                                        344                           \frac{344}{40}=8.6

              50                                        424                           \frac{424}{50}=8.48

Since, ratio of w and t is not constant, relation between number of wheels and number of train cars is not proportional.

5 0
3 years ago
MULTIPLE CHOICE QUESTION
Paha777 [63]

Answer:

i think it will be #3

Step-by-step explanation:

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