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olasank [31]
4 years ago
5

What is the value of in e^4?

Mathematics
2 answers:
True [87]4 years ago
7 0
54.5981500331 is the answer
Sloan [31]4 years ago
7 0

Answer:

The value of the expression is \ln e^4=4    

Step-by-step explanation:

Given : Expression \ln e^4

To find : What is the value of the expression ?

Solution :

Expression \ln e^4

According to logarithmic property,

\ln e^x=x

On comparison with given expression,

Here, x=4

So, \ln e^4=4

Therefore, The value of the expression is \ln e^4=4

You might be interested in
Part E<br> 1e. Subtract the binomial 12y2 – 4y3 from the trinomial 7y - 2y3 + 5y2
bazaltina [42]

Answer:

2y^3-7y^2+7y

Step-by-step explanation:

7y - 2y^3 + 5y^2 - (  12y^2 – 4y^3)

Distribute the minus sign

7y - 2y^3 + 5y^2 - 12y^2 + 4y^3

Combine like terms

2y^3-7y^2+7y

4 0
3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
the point B(-3, -2) is translated 4 units left. what are the coordinates of the resulting point, B’?
ololo11 [35]

Answer:

B'(-7 , -2)

Step-by-step explanation:

First we must understand the coordinate-axis, when we want to move a point to the left or right we do it on the x-axis. to move up or down is on the y axis.

now if we move to the left we go to the negative and to the right the positive

as we are going to move to the left we have to subtract the value that he gave us (4) only to the part of x

B(-3 , -2)

-3 - 4 = -7

B'( -7 , -2)

3 0
3 years ago
Please help me i need it -_-
Natasha2012 [34]
The answer to your question is option b
7 0
3 years ago
Which expression is equivalent to the expression –6.4 – 12 + 4.6?
kow [346]

The answer is -13.8.

Hope this helps!

6 0
3 years ago
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