Question

Solve the following exponential equation:5^x=2 e^x=10​

Answer 1

Number 1.

$5^x=2$, first we will take the $log$ of both of these numbers getting us,

$x=\frac{log(2)}{log(5)}$, which then gives us that $x=0.4306777777....$

Number 2

$e^x=10$, solve for our exponent, $2.718282^x=10$, use the logarithmic formula, and we get,

$x=\frac{log(10)}{log(2.718282)}$, which then we get that $x=2.302585$