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svp [43]
2 years ago
14

Solve the following exponential equation:5^x=2 e^x=10​

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
3 0

Number 1.

5^x=2, first we will take the log of both of these numbers getting us,

x=\frac{log(2)}{log(5)}, which then gives us that x=0.4306777777....

Number 2

e^x=10, solve for our exponent, 2.718282^x=10, use the logarithmic formula, and we get,

x=\frac{log(10)}{log(2.718282)}, which then we get that x=2.302585

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if we sub this back in to the general form, we get:

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