Wow. ok, I didn't expect this to be a triangle question.
You would need to use cosine to solve this.
Side 1: 160<span> opposite angle: </span>58°
<span>Side 2: </span>180<span> opposite angle: </span>73°
<span>Side 3: </span>140<span> opposite angle: </span><span>48°</span>
Answer:
r = 10 , centre = (6, - 2 )
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
given
x² - 12x - 60 = - y² - 4y ( add y² + 4y to both sides )
x² - 12x + y² + 4y - 60 = 0 ( add 60 to both sides )
x² - 12x + y² + 4y = 60
using the method of completing the square
add ( half the coefficient of the x and y terms )² to both sides
x² + 2(- 6)x + 36 + y² + 2(2)y + 4 = 60 + 36 + 4
(x - 6)² + (y + 2)² = 100 ← in standard form
with centre = (6, - 2 ) and r = 
= 10
5003\4 as a mixed number=125 3\4
divide 4 by 5003 using long division
answer=125 3\4
Endpoint T would be at the coordinates (4, -11)
Answer:
a) <DXC and < CXB are complementary angles
b) Supplementary angles
<AXB and <DXB
<AXC and DXC
Step-by-step explanation:
Complementary angles: Two angles are complementary angles if their sum equals 90°
Supplementary angles: Two angles are Supplementary angles if their sum equals 180°
a) Name a pair of complementary angles
So, <DXC and < CXB are complementary angles
b) Name two Supplementary angles pair
<AXB and <DXB (their sum equals 180°)
<AXC and DXC ((their sum equals 180°))
