for 1st
use the formula of inlargement
A(x,y)when enlarging by scale factor k gives A'(kx,ky)
for 2nd
a=
(2a+3)-(a-5)(2a+2)+a^2
b=
3y(7y-8)
Answer:
Expand it.
(1+2i)^3 is equal to (1+2i)(1+2i)(1+2i).
Multiply everything out (being sure to multiply <em>every</em> term. (1+2i) * (1+2i) = 1+2i+2i+4i^2.
i is the square root of negative one, so i^2 is just -1. 1+2i+2i-4 is what you get from the first two, so now simplify that:
1-4 + 2i+2i = (-3+4i) and now multiply that by (1+2i):
(-3+4i) * (1+2i) = -3 - 6i +4i +8i^2.
Simplify again, and the answer is: -11-2i
Step-by-step explanation:
I hope this helps - really my only tip is don't spend time thinking about what i is, that just hurts your brain. Just remember that i^2 is equal to negative one, and treat it like regular multiplication and you will be fine.
126 divided by 2 = 63
63 x 3 = 189
b = 189
Answer:
75
Step-by-step explanation:
Answer:
y=4x+19
Step-by-step explanation:
y-y1=m(x-x1)
y-(-1)=4(x-(-5))
y+1=4(x+5)
y=4x+20-1
y=4x+19