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Reil [10]
3 years ago
9

The accompanying table describes results from groups of 8 births from 8 different sets of parents. The random variable x represe

nts the number of girls among 8 children. Complete parts​ (a) through​ (d) below
Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Using the discrete probability outputs given in the attached table ; the probability values of having exactly 6 ; and  having 6 or more  girls are :

  • P(X = 6) = 0.111

  • P(X ≥ 6) = 0.1

<u>The </u><u>probability</u><u> of having </u><u>exactly 6 girls</u><u> can be defined as</u> :

  • P(X = 6) = 0.111 (from the discrete probability table)

2.)

<u>The </u><u>probability</u><u> of having </u><u>6 or more</u><u> girls can be defined as</u> :

  • P(X ≥ 6) =  P(X = 6) + P(X = 7) + P(X = 8)

  • From the table attached :

  • P(X ≥ 6) = 0.111 + 0.014 + 0.003 = 0.1

Therefore, the probability of having exactly 6 girls is 0.111 while the probability of having 6 or more girls is 0.1

Learn more : brainly.com/question/18153040

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67000 dollars is placed in an account with an annual interest rate of 8.25%. how much will be in the account after 28 years, to
anastassius [24]

Answer:

The Amount of money in the account after 28 years is $616,674.5

Step-by-step explanation:

Given as :

The principal amount placed in the account = p = $67,000

The rate of interest = r = 8.25%

The time period of amount in the account = t = 28

Let the Amount of money in the account = $A

Now<u>, From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, A = $67,000 × (1+\dfrac{\textrm 8.25}{100})^{\textrm 28}

Or, A = $67,000 × (1.0825)^{28}

Or, A = $67,000 × 9.2041

∴ A = $616,674.7

So, The Amount of money in the account = A = $616,674.5

Hence, The Amount of money in the account after 28 years is $616,674.5  Answer

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cupoosta [38]

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ruslelena [56]
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