The accompanying table describes results from groups of 8 births from 8 different sets of parents. The random variable x represe
nts the number of girls among 8 children. Complete parts (a) through (d) below
1 answer:
Using the discrete probability outputs given in the attached table ; the probability values of having exactly 6 ; and having 6 or more girls are :
<u>The </u><u>probability</u><u> of having </u><u>exactly 6 girls</u><u> can be defined as</u> :
- P(X = 6) = 0.111 (from the discrete probability table)
2.)
<u>The </u><u>probability</u><u> of having </u><u>6 or more</u><u> girls can be defined as</u> :
- P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8)
- From the table attached :
- P(X ≥ 6) = 0.111 + 0.014 + 0.003 = 0.1
Therefore, the probability of having exactly 6 girls is 0.111 while the probability of having 6 or more girls is 0.1
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