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Reil [10]
3 years ago
9

The accompanying table describes results from groups of 8 births from 8 different sets of parents. The random variable x represe

nts the number of girls among 8 children. Complete parts​ (a) through​ (d) below
Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Using the discrete probability outputs given in the attached table ; the probability values of having exactly 6 ; and  having 6 or more  girls are :

  • P(X = 6) = 0.111

  • P(X ≥ 6) = 0.1

<u>The </u><u>probability</u><u> of having </u><u>exactly 6 girls</u><u> can be defined as</u> :

  • P(X = 6) = 0.111 (from the discrete probability table)

2.)

<u>The </u><u>probability</u><u> of having </u><u>6 or more</u><u> girls can be defined as</u> :

  • P(X ≥ 6) =  P(X = 6) + P(X = 7) + P(X = 8)

  • From the table attached :

  • P(X ≥ 6) = 0.111 + 0.014 + 0.003 = 0.1

Therefore, the probability of having exactly 6 girls is 0.111 while the probability of having 6 or more girls is 0.1

Learn more : brainly.com/question/18153040

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The function to the graph is 6
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Lelechka [254]

Answer:11/26=0.423076923077 so it could be .0423

Step-by-step explanation:

7 0
2 years ago
Write the equation of a line that is parallel to {y=0.6x+3}y=0.6x+3y, equals, 0, point, 6, x, plus, 3 and that passes through th
Dominik [7]

y = 0.6x - 3.2  
The general form of the desired equation is 
y = mx + b
 where
 m = slope of the line
 b = y intercept of the line 
 If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
 y = 0.6x + b 
 Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
 y = 0.6x + b
 -5 = 0.6(-3) + b
 -5 = -1.8 + b
 -3.2 = b 
 So the desired equation is now 
y = 0.6x - 3.2
3 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
3. You need to hire a taxi. Taxi A charges $9.25 plus $1.50 per mile. Taxi B charges $10.50 plus $1.25 per mile. Find the number
lapo4ka [179]

Answer:

five miles

Step-by-step explanation:

taxi A: for one mile: 10.75

taxi B: for one mile: 11.75

two miles: A: 12.25 B: 13

three miles: A: 13.75 B: 14.25

four miles: A: 15.25 B: 15.5

five miles: A: 16.75 B: 16.75

5 0
2 years ago
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