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Ostrovityanka [42]
2 years ago
12

Solve 7e^(2x)-5>58. Round to the nearest hundredth.

Mathematics
1 answer:
7nadin3 [17]2 years ago
5 0

Answer:

x\gtrapprox1.1

Step-by-step explanation:

7e^{2x}-5>58

7e^{2x}>63

e^{2x}>9

2x>ln(9)

x>\frac{ln(9)}{2}

x\gtrapprox1.1

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