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2 years ago

Solve for x using the property of bisected diagonals CN=20 ln=6x-2

Mathematics

2 answers:

kari74 [83]2 years ago

6 0

Answer:

Step-by-step explanation:

abc

diamong [38]2 years ago

5 0

<h3>Answer: x=7</h3>

Step-by-step explanation:

Since the diagonals of the parallelogram divide each other in half then:

$\sf LC=NC=20 \ \Longrightarrow LN=2NC=20\cdot 2=40 \\\\ LN=6x-2=40 \\\\6x-2=40 \\\\ 6x=42 \\\\ \boldsymbol {\sf x=7}$

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ABCD is a rectangle. AD = 15, AC = 25, and DC = 20. Find BD.

agasfer [191]

Answer:

Step-by-step explanation:

it is the same length as DC just going diagonal.

(i am not good at explaining in case you could not tell)

6 0

3 years ago

When grading an exam, 90% of a professor's 50 students passed. If the professor randomly selected 10 exams, what is the probabil

Damm [24]

Using the binomial distribution, it is found that there is a:

a) 0.9298 = 92.98% probability that at least 8 of them passed.

b) 0.0001 = 0.01% probability that fewer than 5 passed.

For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial probability distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

90% of the students passed, hence $p = 0.9$ .

The professor randomly selected 10 exams, hence $n = 10$ .

Item a:

The probability is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.9)^{8}.(0.1)^{2} = 0.1937$

$P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874$

$P(X = 10) = C_{10,10}.(0.9)^{10}.(0.1)^{0} = 0.3487$

Then:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1937 + 0.3874 + 0.3487 = 0.9298$

0.9298 = 92.98% probability that at least 8 of them passed.

Item b:

The probability is:

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

$P(X < 5) = 0.0001$

Hence:

0.0001 = 0.01% probability that fewer than 5 passed.

You can learn more about the the binomial distribution at brainly.com/question/24863377

3 0

1 year ago

Someone please help me, I’m doing a final right now, and this question so confusing.

Sauron [17]

Answer:

C and D

Step-by-step explanation:

C: (2,0)

D: (0,4)

4 0

2 years ago

Read 2 more answers

What is the value of 1/2 of (3/4_2/5)÷2 2/4?<br>A.1/16<br>B.25/49<br>C.13/56<br>D.49/100

Aleks04 [339]

Answer:

6 ka value 6 hai

1 ka value 10 hai

6 0

2 years ago

Read 2 more answers

What is the equation of a line that passes through (0.8) and (3,6)?

nirvana33 [79]

Answer:

$y=\frac{-2}{3}x+8$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)