The dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
Let's suppose x and y are the sides of the rectangular garden and y is the parallel to the river.
Then according to the problem:
2x + y = P ..(1)
P is the perimeter of the rectangle.
xy = 405000 (area of the rectangle)
Plug the value of y in the equation (1) from the above equation.
P(x) = 2x + 405000/x
P'(x) = x—405000/x² = 0
x = 450 m
P''(x) > 0 hence at x = 450 the value of P(x) is minimum.
y = 405000/450
y = 900 m
P(min) = 1800 m
Thus, the dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.
Learn more about the rectangle here:
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If you're trying to solve for x, keep in mind the ln (natural log) of e is 1. So take the natural log of both sides, which will give you ln Y = ln e^x. The ln and e essentially cancel out, so you're left with x = ln Y.
17% would be 17/100. or 67%=67/100. 46% = 46/100 (simplify!) see the pattern? hope it helps!
Answer:
6 7/12
Step-by-step explanation:
We need to get a common denominator, which is 12
12 1/4 - 5 2/3
12 1/4*3/3 - 5 2/3*4/4
12 3/12 - 5 8/12
We will need to borrow from the 12 since 3/12 is less than 8/12. Write the 1 we borrow as 12/12
11 + 12/12 + 3/12 - 5 8/12
11 15/12 - 5 8/12
6 7/12
Answer: b = 3
Step-by-step explanation:
1. a^2 + b^2 = c^2
2. 1.6^2 + b^2 = 3.4^2
3. 2.56 + b^2 = 11.56
4. 11.56-2.56 = b^2
5. 9 = b^2
6. 3 = b
