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Maru [420]
2 years ago
5

A scientist needs 60 liters of a 40% solution of alcohol.He has a 30% solution and a 60% solution available.How many liters of t

he 30% solution and how many liters of the 60% solution should he mix to make the 40% solution?
Mathematics
1 answer:
stich3 [128]2 years ago
8 0

Answer:

He should mix 25 liters of the 30% solution, and 35 liters of 60% solution.

Step-by-step explanation:

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PLEASE HELP IM DESPERATE WILL GIVE BRAINLIEST ONLY ANSWER IF YOU ARE HELPING
VARVARA [1.3K]

Answer:

48

Step-by-step explanation:

u • w

= (i + 6j ) • (9i - 2j )

= (1 × 9 ) + (6 × - 2 )

= 9 + (- 12)

= 9 - 12

= - 3

v • w

= (5i - 3j ) • (9i - 2j )

= (5 × 9) + (- 3 × - 2)

= 45 + 6

= 51

Then

u • w + v • w

= - 3 + 51

= 48

7 0
3 years ago
Let sin(−θ)=−3/5 and tanθ>0. What is the value of cos(−θ)?
Jobisdone [24]

Answer:

The value of  Cos (-Ф) \dfrac{\textrm 4}{\textrm 5} .

Step-by-step explanation:

Given Trigonometric function as :

sin( - Ф ) = \frac{- 3}{5}

- sin Ф = \frac{- 3}{5}

So, sin Ф = \frac{ 3}{5}

Now, as sin Ф = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

So ,  \dfrac{\textrm perpendicular}{\textrm hypotenuse} =  \frac{ 3}{5}

So, perpendicular = 3

And hypotenuse = 5

Now,<u> From Pythagoras Theorem</u>

Base ² = Hypotenuse² - Perpendicular²

Or, Base ² = 5² - 3²

Or, Base ² = 25 - 9

Or, Base ² = 16

∴  Base = \sqrt{16}

I.e Base = 4

Now, Cos Ф =  \dfrac{\textrm base}{\textrm hypotenuse}

So, Cos Ф =  \dfrac{\textrm 4}{\textrm 5}

Now , Since

Cos ( - Ф ) = Cos Ф

So,  Cos ( - Ф ) = Cos Ф =  \dfrac{\textrm 4}{\textrm 5}

Hence The value of  Cos (-Ф) \dfrac{\textrm 4}{\textrm 5} . Answer

6 0
2 years ago
Please help me on this it’s due tomorrow:(((
BigorU [14]

Answer:

Bro

Step-by-step explanation:

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7 0
2 years ago
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Use a table of values with at least 5 values to graph the following function:
34kurt

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0
1 year ago
Solve the following quadratic equation. *<br> x^2+12x-45=0
liq [111]

Answer:

9 over 5

Step-by-step explanation:

8 0
3 years ago
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