The expected value of the game is the mean value of the game
The expected value of the game is $1
<h3>How to determine the expected value?</h3>
There are 13 spades in a deck of card of 52
So, the probability of selecting a spade is:
P(Spade) = 13/52
Simplify
P(Spade) = 1/4
Winning = $7
The probability of not selecting a spade is:
P(Not spade) = 1 - 1/4
Simplify
P(Not spade) = 3/4
Lose = $1
The expected value of the game is:
This gives
Simplify
Evaluate
Hence, the expected value of the game is $1
Read more about expected values at:
brainly.com/question/15858152
11 cm? Im not that good at this.. If im correct any of those would work
your x-intercept is 3 and I don't know why I have to do 20 characters for an answer that involves 3 words and 1 number
Answer:
b. Yes, probability is > 0.05
Step-by-step explanation:
We have to find P(X=3) and if the probability is below 0.05 then the it would be unusual and if it isn't below 0.05 we believe that the data from the blood program.
This probability can be found bu binomial distribution with parameters n=6
and p=0.4.
P(X=x)=nCx(p^x)(q^n-x)
where q=1-p=1-0.4=0.6.
P(X=3)=6C3(0.4^3)(0.6^3)
P(X=3)=20(0.064)(0.216)
P(X=3)=0.27648
As the probability that the three have a blood group is greater than 0.05, so, we believe that the data from the blood program.
90/15-7/15=83/15 the correct answer to this equation.
