Answer:
a=7/2
Step-by-step explanation:
a^2-2a+2a-4-a^2+2a+3a+6=3a+9
You want to solve for "a"
1. Mover all terms on the right side to the left side setting this equation to zero.
2. Combine Like Terms
3. Divide to isolate your "a"
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
12•1
13•6
12/78 divide both numbers by 6 to simplify
Answer- 2/13
Answer:
Can you post 4.3? We need more information to answer this.
Step-by-step explanation:
Answer:
A multiplicative inverse of a real number x is a real number y such that xy = 1. ... ((NOT GOOGLING DEF))
Step-by-step explanation:
"For every real number x, if x 0, then there is a real number y such that xy = 1.”
