What is the area of a sector with a central angle of 2pi/9 radians and a diameter of 20.6mm? Use 3.14 for Ali and round your ans wer to the nearest hundredth.
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- The area of the circle is: A=πr² A is the area of the circle. π=3.14 r is the radius of the circle. - To calculate the area of <span> the sector indicated in the problem, you must apply the following formula: As=(</span>θ/2π)πr² As is the area of the sector. θ is the central angle (θ=2π/9) π=3.14 r is the radius. - First, you must find the radius: r=Diameter/2 r=20.6 mm/2 r=10.3 mm - Now, you can substitute the values into the formula As=(θ/2π)πr². Then, you have: As=(θ/2π)πr² As=(2π/9/2π)(π)(10.3)² As=(π/9π)(π)(10.3)² As=(3.14/9x3.14)(3.14)(10.3)² - Finally, the area of the sector is: As= 37.01 mm²
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