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2 years ago

Simplify this fraction. 6/5

Mathematics

2 answers:

mixer [17]2 years ago

7 0

Answer:

6/5 is the lowest term.

Step-by-step explanation:

erik [133]2 years ago

5 0

Answer:

Mixed Number: 1 1/5

Decimal: 1.2

Step-by-step explanation:

6/5 is already in the simplest form. It can be written as 1.2 in decimal form (rounded to 6 decimal places).

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator

GCD of 6 and 5 is 1

Divide both the numerator and denominator by the GCD

6 ÷ 1/5 ÷ 1

Reduced fraction: 6/5

Therefore, 6/5 simplified to lowest terms is 6/5.

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kvv77 [185]

Answer:

Step-by-step explanation:

Part 1

P(z < -1.45)

Using the z score table

P =

Part 2

We solve using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) P(X >52)

x = 52

Mean = 60

Standard deviation = 8

z = 52 - 60/8

z = -1

P-value from Z-Table:

P(x<52) = 0.15866

P(x>52) = 1 - P(x<52) = 0.84134

b) P(48 < x < 64)

5 0

2 years ago

The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability d

ollegr [7]

Answer: 0.70

Step-by-step explanation:

Given : The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution:

x 0 1 2 3 4 5

P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05

Using the above probability distribution , the the probability that in a given week there will be at most 3 accidents is given by :_

$P(\leq3)=P(0)+P(1)+P(2)+P(3)\\\\=0.20+0.30+0.20=0.70$

Hence, the required probability = 0.70

7 0

2 years ago

Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3

Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

$\frac{dV}{dt} = -kA$

Using Euler's method

$\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i} \\$

Where initial droplet volume is:

$V(0) = \frac{4pi}{3} * r(0)^3 = \frac{4pi}{3} * 2.5^3 = 65.45 mm^3$

Hence, the iterative solution will be as next:

i = 1, ti = 0, Vi = 65.45

$V'_{i} = -k *4pi*(\frac{3*65.45}{4pi})^(2/3) = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88$

i = 2, ti = 0.5, Vi = 63.88

$V'_{i} = -k *4pi*(\frac{3*63.88}{4pi})^(2/3) = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33$

i = 3, ti = 1, Vi = 62.33

$V'_{i} = -k *4pi*(\frac{3*62.33}{4pi})^(2/3) = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813$

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

$r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\$

The average change of droplet radius with time is:

Δr/Δt = $\frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min$

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0

3 years ago

Plz help..................

Misha Larkins [42]

The answer isn't A or B because those two are not factored. D is wrong because 8•8=64 not 16. So that leaves us with C (4•4=16).

7 0

2 years ago

Give an example of a function from the set of integers to the set of positive integers that is g

BaLLatris [955]

The function ...

... g = |x| + 1

will map any integer x into the set of positive integers g.

3 0

3 years ago