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Scrat [10]
3 years ago
7

Consider the following data set: 0, 10, 12, 3, 13, 7, 2, 5 Find the upper quartile.

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

11

Step-by-step explanation:

The upper quartile Q3 is the median of the upper half of the data.

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Converting centimeters to the units of inches, we have to multiply a value with 2.54. From this, we can say that the relationship is linear. A linear relationship can be represented by an equation such as:

y = kx

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What are the discontinuities of the function f(x) =x<2-36/4x-24 ?
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Well, 2-36/4x-24 is the same as (2-24)-(36/4)x which simplifies to -22-9x. This does not have a discontinuity anywhere. If you meant to divide 36 by 4x, then x=0 would be the discontinuity since you cannot divide by 0. If you meant to have 4x-24 all in the denominator, then x=6 is the discontinuity since that would make the bottom equal 0. So it seems you need some parenthesis here somewhere for your problem to make sense.
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How do you simplify the square root of 50
pshichka [43]
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Given the functions f(x) = 3x2, g(x) = x2 − 4x + 5, and h(x) = –2x2 + 4x + 1, rank them from least to greatest based on their ax
worty [1.4K]
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x = \frac{-b}{2a} = \frac{-0}{2(3)} = \frac{0}{6} = 0
f(x) = 3x²
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f(0) = 3(0)
f(0) = 0
(x, f(x)) = (0, 0)

g(x) = x² - 4x + 5
x = \frac{-b}{2a} = \frac{-(-4)}{2(1)} = \frac{4}{2} = 2
g(x) = x² - 4x + 5
g(2) = (2)² - 4(2) + 5
g(2) = 4 - 8 + 5
g(2) = -4 + 5
g(2) = 1
(x, g(x)) = (2, 1)

h(x) = -2x² + 4x + 1
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h(x) = -2x² + 4x + 1
h(1) = -2(1)² + 4(1) + 1
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h(1) = -2 + 5
h(1) = 3
(x, h(x)) = (1, 3)
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