2 years ago

What is the value of 4C9 ?

1 answer:

vekshin12 years ago

7 0

The answer is 0

The formula is

n!/ r!(n-r)!

4!/ 9!(4-9)!

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NNADVOKAT [17]

Answer: $\frac{2x(5x + 1)}{4x - 1}$

<u>Step-by-step explanation:</u>

$\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2}$ ÷ $\frac{2x^{2}-6x}{5x^{2}+11x + 2}$

= $\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}$ ÷ $\frac{2x(x - 3)}{(5x + 1)(x + 2)}$

= $\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}$ x $\frac{(5x + 1)(x + 2)}{2x(x - 3)}$

= $\frac{2x(5x + 1)}{4x - 1}$

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kondor19780726 [428]

Answer:

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Step-by-step explanation: Took assignment on edge

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Kobotan [32]

Answer:

I think it's right answer is 530

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2 years ago

mina [271]

Oh shucks, that's crazy man

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2 years ago

dmitriy555 [2]

Answer:

what exactly am i solving for ?

Step-by-step explanation:

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2 years ago