Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x 2) f(x) = (x – 2)(x 2) f(x) = (x 1)(x – 2)
1 answer:
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Answer:
First inequality: y >
Second inequality: y < 3 + x
Explanation:
The inequality in slope-intercept form has the following general formula:
y < mx + c or y > mx + c (according to the given sign)
where m is the slope and c is the y-intercept
This means that to get any inequality in slope-intercept form, we will have to isolate the y on one side of the inequality.
First given inequality:
4x - 5y < 1
4x - 5y + 5y < 1 + 5y
1 + 5y > 4x
1 + 5y - 1 > 4x - 1
5y > 4x - 1
y >
comparing this to the general form, we would find that:
slope (m) = 4/5
y-intercept (c) = 1/5
Second given inequality:
y - x < 3
y - x + x < 3 + x
y < 3 + x
comparing this to the general form, we would find that:
slope (m) = 1
y-intercept (c) = 3
Hope this helps :)
First inequality: y >
Second inequality: y < 3 + x
Explanation:
The inequality in slope-intercept form has the following general formula:
y < mx + c or y > mx + c (according to the given sign)
where m is the slope and c is the y-intercept
This means that to get any inequality in slope-intercept form, we will have to isolate the y on one side of the inequality.
First given inequality:
4x - 5y < 1
4x - 5y + 5y < 1 + 5y
1 + 5y > 4x
1 + 5y - 1 > 4x - 1
5y > 4x - 1
y >
comparing this to the general form, we would find that:
slope (m) = 4/5
y-intercept (c) = 1/5
Second given inequality:
y - x < 3
y - x + x < 3 + x
y < 3 + x
comparing this to the general form, we would find that:
slope (m) = 1
y-intercept (c) = 3
Hope this helps :)