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Norma-Jean [14]
2 years ago
12

Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x 2) f(x) = (x – 2)(x 2) f(x) = (x 1)(x – 2)

Mathematics
1 answer:
makvit [3.9K]2 years ago
8 0

The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)

<h3>How to determine the function?</h3>

For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:

(h,k) = (0,y)

A quadratic function is represented as:

f(x) = (x - h)^2 + k

So, we have:

f(x) = (x - 0)^2 + k

Evaluate

f(x) = x^2 + k

From the list of options, we have:

f(x) = (x - 2)(x + 2)

Expand

f(x) = x^2 - 4

Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)

Read more about vertex at:

brainly.com/question/18797214

#SPJ4

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Identify the center and radius for the circle with the following equation; (x+5)^2+y^2+12y=3
rosijanka [135]
Center: (-5,-6)
Radius: 39
How to do it

Complete the square for
y
2
+
12
y
y
2
+
12
y
.

(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
Substitute
(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
for
y
2
+
12
y
y
2
+
12
y
in the equation
(
x
+
5
)
2
+
y
2
+
12
y
=
3
(
x
+
5
)
2
+
y
2
+
12
y
=
3
.
(
x
+
5
)
2
+
(
y
+
6
)
2
−
36
=
3
(
x
+
5
)
2
+
(
y
+
6
)
2
-
36
=
3
Move
−
36
-
36
to the right side of the equation by adding
36
36
to both sides.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
Add
3
3
and
36
36
.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
This is the form of a circle. Use this form to determine the center and radius of the circle.
4 0
3 years ago
Inequality<br> 5+m&gt;4 or 7m&lt;-35
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5+m > 4\ or\ 7m < -35\\\\\#1\\5+m > 4\ \ \ \ |subtract\ 5\ from\ both\ sides\\\\m > -1\\\\\#2\\7m < -35\ \ \ \ \ |divide\ both\ sides\ by\ 7\\\\m < -5\\\\Answer:m\in(-\infty;-5)\ \cup\ (-1;\ \infty)
8 0
4 years ago
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