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kolezko [41]
2 years ago
12

How close does the proton get to the line of charge?

Physics
1 answer:
loris [4]2 years ago
3 0

Answer:

12 cm

Explanation:

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If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate
pogonyaev
Let h =  distance (m) to the water surface.

Initial velocity, u  = 0 (because the stone was dropped).
Use the formula
 h = ut + (1/2)gt^2
  where g = 9.8 m/s^2  (acc. due to graity)
              t = time (s)

h = (1/2)*(9.8)*(3^2) = 44.1 m
8 0
3 years ago
6.If a 250. gram cart moving to the right with a velocity of .31 m/s collides inelastically with a 500. gram cart traveling to t
spin [16.1K]

Answer:

The total momentum of the system before the collision is 0.0325 kg-m/s due east direction.    

Explanation:

Given that,

Mass of the cart, m = 250 g = 0.25 kg

Initial velocity of the cart, u = 0.31 m/s (due right)

Mass of another cart, m' = 500 g = 0.5 kg

Initial velocity of the another cart u' = -0.22 m/s (due left)

Let p is the total momentum of the system before the collision. It is given by :

p=mu+m'u'\\\\p=0.25\times 0.31+0.5\times (-0.22)\\\\p=-0.0325\ kg-m/s

So, the total momentum of the system before the collision is 0.0325 kg-m/s due east direction.            

5 0
3 years ago
Read 2 more answers
A 1451 kg car is traveling at 48.0 km/h. How much kinetic energy does it possess? K.E. =
jarptica [38.1K]

           Kinetic energy  =  (1/2) (mass) (speed)²

BUT . . . in order to use this equation just the way it's written,
the speed has to be in meters per second.  So we'll have to
make that conversion.

        KE  =  (1/2) · (1,451 kg) · (48 km/hr)² · (1000 m/km)² · (1 hr/3,600 sec)²

               =  (725.5) · (48 · 1000 · 1 / 3,600)²  (kg) · (km·m·hr / hr·km·sec)²

               =  (725.5) · ( 40/3 )²  ·  ( kg·m² / sec²)

               =    128,978  joules  (rounded)
8 0
3 years ago
A molecule that moves across a cell membrane without using the cell’s energy tends to move
zaharov [31]

Answer:answer is b

Explanation:

4 0
3 years ago
_ NaBr + __ H3PO4 → ___ Na3PO4 + __ HBr
algol [13]

Answer:

The balanced equation is 3NaBr+1H3PO4 ----> 1Na3PO4 + 3HBr

This is a double replacement because you are switching both the Na and the Hydrogen.

Explanation:

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3 years ago
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