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kolezko [41]
3 years ago
12

How close does the proton get to the line of charge?

Physics
1 answer:
loris [4]3 years ago
3 0

Answer:

12 cm

Explanation:

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What it 1 Newton force<br>​
mote1985 [20]

Answer:

 1 kg⋅m⋅s−2

Explanation:

I cant really explain it, but thata the answer

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An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D
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A high quality insecticide applied all along the axis and the surrounding area can protect against a recurrence for a substantial period of time.
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3 years ago
Calculate the magnitude and the direction of the resultant forces​
snow_tiger [21]

answer:

resultant = 127.65 in the positive direction

explanation:

F1 = 50N , F2 = 40N, f3 = 55N , f4 = 60N

Fy = 50 sin 50 = 50 × -0.26 = -13

Fx = 40 cos 0 = 40×1 = 40

fx = 55 cos 25 = 55×0.99 = 54.45

Fy = 60 sin 70 = 60 × 0.77 = 46.2

resultant = -13+40+54.45+46.2 = 127.65 in the positive direction

6 0
3 years ago
Damage to internal organs will present as pain associated with a particular surface area of the body. Why would something like i
GenaCL600 [577]
A dish shaped large muscle which moves up and down when there is contraction and expansion of lungs is the diaphragm which is present between the chest cavity and lower abdominal region. The action of the diaphragm is affected by an inflammation occurring below the muscular disc which will affect the process of breathing. The forceful breathing may result in strain and stress in the back muscles of the human body. This in turn causes pain in the shoulder.
4 0
3 years ago
A 0.12 kg body undergoes simple harmonic motion of amplitude 8.5 cm and period 0.20 s. (a) What is themagnitude of the maximum f
Neporo4naja [7]

Answer:

a)F=698.83 N

b)K=8221.56 N/m

Explanation:

Given that

mass ,m = 0.12 kg

Amplitude ,A= 8.5 cm

time period ,T = 0.2 s

We know that

T=\dfrac{2\pi}{\omega}

{\omega}=\dfrac{2\pi }{0.2}\ rad/s

{\omega}=31.41\ rad/s

We know that

{\omega}^2=m\ K

K=Spring constant

K=\dfrac{\omega^2}{m}

K=\dfrac{31.41^2}{0.12}\ N/m

K=8221.56 N/m

The maximum force F

F= K A

F= 8221.56 x 0.085 N

F=698.83 N

a)F=698.83 N

b)K=8221.56 N/m

3 0
4 years ago
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