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olchik [2.2K]
3 years ago
9

What is the car's average velocity (in m/s) in the interval between t = 0.5 s to t = 2 s?

Physics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

1.0\; \rm m \cdot s^{-1}.

Explanation:

Consider a time period of duration \Delta t. Let change in the position of an object during that period of time be denoted as \Delta x. The average velocity of that object during that period would be:

\displaystyle \bar{v} = \frac{\Delta x}{\Delta t}.

For the toy car in this question, the time interval has a duration of 2.0 \; \rm s - 0.5\; \rm s = 1.5\; \rm s. That is: \Delta t = 1.5\; \rm s. (One decimal place, two significant figures.)

On the other hand, what would be the change in the position of this toy car during that 1.5\; \rm s?

Note, that from readings on the snapshot in the diagram:

  • The position of the toy car was 0.1\; \rm m at t = 0.5\; \rm s (the beginning of this 1.5-second time period.)
  • The position of the toy car was 1.6\; \rm m at t = 2.0\; \rm s (the end of this 1.5-second time period.)

Therefore, the change to the position of this toy car over that time period would be \Delta x = 1.6\; \rm m - 0.1\; \rm m = 1.5\; \rm m. (One decimal place, two significant figures.)

The average velocity of this car over this period of time would thus be:

\displaystyle \bar{v} = \frac{\Delta x}{\Delta t} = \frac{1.5\; \rm m}{1.5\; \rm s} = 1.0\; \rm m \cdot s^{-1}. (Two significant figures.)

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c )

Outside of r = r₂

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ergo
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<h3>How to convert micrograms to decigrams?</h3>

According to this question, 450 micrograms of a sample of gold is needed but we only have a mass balance that measures in decigrams.

This means that we are to convert the amount of gold you need to decigrams by comparing the exponents.

The conversion factor of micrograms to decigrams is as follows:

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Question 8
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For this question in particular, initial displacement is maximum at 8cm, so it is used the cosine function:

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