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telo118 [61]
3 years ago
8

what is it called when a soccer ball accelerates faster than a bowling ball when the same amount of force is applied?

Physics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

Answer: 2nd Law - The soccer ball weighs less than the bowling ball, so you need less force to get it to have the same acceleration as the bowling ball.

Explanation:

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An empty container has a mass of 3 g. When it is filled with 5 cm3 of a liquid,
IrinaK [193]

Answer:

THE MASS OF THE LIQUID IS 22.5 g

Explanation:

Density = 0.180 g/cm3

Side length = 5 cm

Mass = unknown

To calculate the mass of the liquid, we use the formula:

Mass = density * volume

Volume of a cube or cuboid container = l^3

Volume = 5 ^3 = 125 cm3

So therefore, the mass of the liquid is:

Mass = 0.180 * 125

Mass = 22.5 g

In conclusion, the mass of the liquid in the container is 22.5 g

3 0
3 years ago
Consider the following situations:
Snezhnost [94]

Answer:

Though no question is specified here but let analyzed experiences of each

Explanation:

1. Required a force to stop it (Law of inertial). Constant acceleration

2. will have reduced acceleration (deceleration)

3. Uniform acceleration may set in. it accelerate

4. maximized it speed since no friction affect it motion

5. accelerating. Vo=0 and V gradually increased

6. less or no friction opposes the motion

7. It  experience reduce motion based on air friction

8. constant acceleration due to gravity

9. g can be a bit affected but still about equal

4 0
4 years ago
Alex drives 1900 meters in 200 s. Assuming he does not speed up or slow down, what is his speed?
pochemuha
Alex is driving at 21.2508882 miles per hour
8 0
1 year ago
You are driving your 1700 kg car at 21 m/s down a hill with a 5.0∘ slope when a deer suddenly jumps out onto the roadway. You sl
podryga [215]

Answer:

d = 27.7 m

Explanation:

Here the car is driving on the inclined plane

So here we can say that work done by the gravity and work done by friction is equal to change in kinetic energy of the system

So here we can write it as

mgsin\theta \times d - F_f \times d = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

now we have

m = 1700 kg

v_f = 0

v_i = 21 m/s

F_f = 1.5 \times 10^4 N

(1700)(9.81)sin5 (d) - (1.5\times 10^4)d = 0 - \frac{1}{2}(1700)(21^2)

1453.5 d - (1.5\times 10^4)d = -374850

d = 27.7 m

6 0
3 years ago
The magnet below is cut in half. what will be the result?
loris [4]

Answer:

the correct would be c

Explanation:

a magnet will always have a north and a south so if you cut the magnet in half the north part would have a south on the opposite end and vice versa .

3 0
3 years ago
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