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Ulleksa [173]
3 years ago
10

A proton initially has V=4.0 i -2.0 j +3.0 k and then 4 seconds later has v= -2.0 i -2.0 j +5.0 k (in meters per second).A) For

that 4 seconds, what is the protons average acceleration in unit vector notationB) What is the proton's average acceleration in magnitude and find the angle between the average acceleration vector and the positive direction of the x-axis?
Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

Explanation:

\overrightarrow{u}=4\widehat{i}-2\widehat{j}+3\widehat{k}

\overrightarrow{v}=-2\widehat{i}-2\widehat{j}+5\widehat{k}

time, t = 4 s

(a) Acceleration is defined as the rate of change of velocity.

\overrightarrow{a}=\frac{\overrightarrow{v}-\overrightarrow{u}}{t}

\overrightarrow{a}=\frac{-2\widehat{i}-2\widehat{j}+5\widehat{k}-4\widehat{i}+2\widehat{j}-3\widehat{k}}{4}

\overrightarrow{a}=-1.5\widehat{j}+0.5\widehat{k}

(b) Magnitude of acceleration is

a = \sqrt{(-1.5)^{2}+(0.5)^{2}}

a = 1.58 m/s²

It is parallel to x axis.

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artcher [175]

Answer:

3.True. The magnitude of momentum is the same

Explanation:

Let's propose the solution of the problem

The initial moment is

                     p₀ = m v

The final moment

                     p_{f} = m (-v)

 

                  p₀ = - p_{f}

Now we can review the claims

1. False. We see that the moment module is the same, but its direction changes

2. False. The impulse is a vector

3.True. The magnitude of momentum is the same

7 0
3 years ago
Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel an
Nataliya [291]

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

W = F\cdot \Delta s

Where:

W - Work, measured in joules.

F - Force exerted on the object, measured in newtons.

\Delta s - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

W_{net} = W_{Joel} - W_{Jerry}

W_{net} = F\cdot \Delta s - F\cdot \Delta s

W_{net} = (F-F)\cdot \Delta s

W_{net} = 0\cdot \Delta s

W_{net} = 0\,J

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

W_{net} = W_{Joel}

W_{net} = F\cdot \Delta s

Hence, the work done by Joel is greater than the work done by Jerry.

7 0
3 years ago
Explain the why a constant speed has a slope of 0 on a graph of speed v.time.
Studentka2010 [4]
Because if I do 0*time you get the answer as 0
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3 years ago
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

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3 years ago
What was the greatest discovery by galileo during his inclined-plane experiments?
Sergeeva-Olga [200]
Galileo discovered during his inclined-plane experiments that a ball rolling down an incline and onto a horizontal surface would roll indefinitely.
3 0
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