Using kinematics we can find that the take-off distance is 6163 ft
Given parameters
- The initial and final speed of the plane i = 0 and v = 140 mph
To find
The measurement system allows not to have problems when working in different units, in this case we reduce the speed units
v = 140 mile / h (5280 ft / mile) (1h / 3600 s) = 205.34 ft / s
The kinematics allows to find the relationships between the position, the speed and the acceleration of a body, in this case the movement is in one dimension.
v = v₀ + a t
where v and v₀ are the final and initial velocity, respectively, at acceleration and t the time
a =
a =
a = 3.42 ft / s²
Let's use the expression
v² = v₀² + 2 a x
Where v and v₀ are the final and initial velocity, respectively, at acceleration and x the distance traveled
x =
x =
x = 6163.8 ft
Let's reduce to miles
x = 6163.8 ft (1 mile / 5280 ft)
x = 1.17 mile
In conclusion using kinematics we can find that the take-off distance is 6163 ft
Learn more about kinematics here:
Answer:
no picture or anything so cant anwser
Explanation:
d = distance to which the grocery cart is pushed = 18 m
f = frictional force = 37.5 N
θ = angle of force below the horizontal = 27.5 deg
W = gravitational force in downward direction
Θ = angle between gravitational force in down direction and displacement in horizontal direction = 90
U = work done on the cart by gravitational force
work done on the cart by gravitational force is given as
U = W d CosΘ
inserting the values
U = W (18) Cos90
U = 0 J
Answer:
wavelength= 1.05 × 10^ -46 m
Explanation:
the formula : λ= hc/E
where; "h" = Planck's constant [6.626 × 10^ -34]
c= speed of light [3.0 × 10^ 8]
you first have to convert the energy of the photon to Joules by dividing the constant by 1000
2.09 × 10^ -18 / 1000 = 2.09 × 10^ -21
then you replace you data into the equation
λ= 6.626 × 10^ -34 × 3.0 × 10^ 8 / 2.09 × 10 ^ -21
first multiply the Planck's constant and the speed of light then divide it by the energy which is in "Joules"
:. λ = 1.05 × 10^ -46
hope this helps