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3 years ago

Please help on these two thanks

Physics

1 answer:

Lisa [10]3 years ago

4 0

Explanation:

Number 29

= 10 N (from rocket) + 10 N (from wheels) - 7 N (from parachute 'cause force in other direction)

= 20 N - 7 N

= 13 N ✔

Number 30

= 100 N - 85 N

= 15 N to the left ✔

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Jumps at 8 m/s at a 30 degree angle above the horizontal. how long was she in the air?

pentagon [3]

Vo = 8 m/s. g = 10 m/s^2
alpha = 30 degree
ask: x?

x = vo^2 sin ^2 alpha / g
x = 8 ^2 x 2 sin 30 cos 30 / 10
x =( 64 x2x 1/2x1/2√3 )/ 10
x= 3.2 √3 metres

√3 = 1.73

4 0

3 years ago

The predicted location of Neptune was made possible because _____.

Neko [114]

Answer:

B. of a detailed study of uranus.

Explanation:

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3 years ago

A 910-kg object is released from rest at an altitude of 1200 km above the north pole of the Earth. If we ignore atmospheric fric

gayaneshka [121]

In order to develop this problem it is necessary to use the concepts related to the conservation of both potential cinematic as gravitational energy,

$KE = \fract{1}{2}mv^2$

$PE = GMm(\frac{1}{r_1}-(\frac{1}{r_2}))$

Where,

M = Mass of Earth

m = Mass of Object

v = Velocity

r = Radius

G = Gravitational universal constant

Our values are given as,

$m = 910 Kg$

$r_1 = 1200 + 6371 km = 7571km$

$r_2 = 6371 km,$

Replacing we have,

$\frac{1}{2} mv^2 = -GMm(\frac{1}{r_1}-\frac{1}{r_2})$

$v^2 = -2GM(\frac{1}{r_1}-\frac{1}{r_2})$

$v^2 = -2*(6.673 *10^-11)(5.98 *10^24) (\frac{1}{(7.571 *10^6)} -\frac{1}{(6.371 *10^6)})$

$v = 4456 m/s$

Therefore the speed of the object when striking the surface of earth is 4456 m/s

3 0

4 years ago

What would be the mass of an object that has a force of 88N and an acceleration of 12 m/s2?

MA_775_DIABLO [31]

Answer:

7.33 kg

Explanation:

F = ma

88 N = m(12 m/s^2)

m = 7.33 kg

6 0

3 years ago

In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation

mr_godi [17]

Answer:

the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

Explanation:

The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:

$W_{Demand} = W_{Supply}$

15 - (1/200) L = 5 + (1/200) L

15 - 5 = (1/200) L + (1/200) L

10 = (2/200) L

(10*200)/2 = L

1000 = L

Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:

W = 15 - (1/200) L

W = 15 - (1/200) 1000

W = 10

Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

7 0

3 years ago