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3 years ago

The Ancient Roman economy did not make use of

Physics

2 answers:

denis-greek [22]3 years ago

5 0

Answer:

D paper money. The ancient Romans did not use any paper money instead their currency was coins.

ser-zykov [4K]3 years ago

3 0

D. Paper Money

All of the other ones mentioned were used in Ancient Rome.

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Eric drops a 2.20 kg water balloon that falls a distance of 45.08 m off the top of a

Marianna [84]

Answer:

972 J

Explanation:

At the bottom, all the gravitational potential energy was converted into kinetic energy. If you calculate the GPE, its value will be the same that the KE at the bottom. The GPE can be calculated this way:

GPE = mass×gravity×heigth

GPE = 2.2×9.8×45.08 ≈ 972

4 0

2 years ago

a football quarterback throws a football. after it leaves his hand, what forces are acting on the football? choose all that appl

MAVERICK [17]

golekeeper

Explanation:

because they use hand to save keeper

3 0

2 years ago

Momentum is mass times .

anzhelika [568]

Answer:True

Explanation:

4 0

3 years ago

Read 2 more answers

How many days does the earth take to rotate around the sun

ValentinkaMS [17]

Answer:

1 day

Explanation:

The spinning movement of Earth around its axis is known as Earth's rotation.

The Earth rotates around the Sun in 1 day that is 24 hours but once in every 23 hours, 56 minutes, and 4 seconds with respect to other stars.

According to the Indian astronomer Aryabhata, Earth rotates about its axis daily.

3 0

3 years ago

he capacitor can withstand a peak voltage of 550 VV . If the voltage source operates at the resonance frequency, what maximum vo

anygoal [31]

Answer:

The maximum voltage is 39.08 V.

Explanation:

Given that,

Voltage = 550 V

Suppose, In an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is $1.20\times10^{-2}\mu F$

We need to calculate the resonant frequency

Using formula of resonant frequency

$f=\dfrac{1}{2\pi\sqrt{LC}}$

Put the value into the formula

$f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}$

$f=2356.8\ Hz$

We need to calculate the maximum current

Using formula of current

$I=\dfrac{V_{c}}{X_{c}}$

$I=2\pi f C\times V_{c}$

Put the value into the formula

$I=2\pi\times2356.8\times1.20\times10^{-8}\times550$

$I=0.0977\ A$

We need to calculate the impedance of the circuit

Using formula of impedance

$Z=\sqrt{R^2+(X_{L}-X_{C})^2}$

At resonant frequency , $X_{L}=X_{C}$

So, Z = R

We need to calculate the maximum voltage

Using formula of voltage

$V=IR$

Put the value into the formula

$V=0.0977\times400$

$V=39.08\ V$

Hence, The maximum voltage is 39.08 V.

4 0

3 years ago