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3 years ago

Which adaptation would be most likely to help a prey species avoid predators?

2 answers:

5 0

Anti-predator mechanisms are mechanisms developed by prey through evolution or a learning process. The following are the most common mechanisms.

Camouflage, Living Underground, Nocturnality and Apostatic Selection.

Apostatic Selection is an evolutionary process that allows the survival of less frequent species of the same prey.

Nocturnality: Preys whose predator hunt during the day tend to live and hunt for food at night to avoid the predators.

Camouflage: This involves taking the colour of an object or natural habitat to avoid the predator.

zhenek [66]3 years ago

4 0

Camouflage adaptation will most likely help a prey avoid a predator . #answerwithquality #BAL

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2. A sample of gas has a pressure of 195 kPa and a volume of 3.50 L. If the pressure

zhannawk [14.2K]

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we're finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

We have

$V_2 = \frac{195000 \times 3.5}{150000} = \frac{682500}{150000} \\ = 4.55$

We have the final answer as

Hope this helps you

7 0

3 years ago

Derivative for tan(x)

Maksim231197 [3]

Answer:

sec² (x)

Explanation:

Use the trigonometric ratio definition of the tangent function and the quotient rule.

tan(x) = sin(x) / cos(x)

Quotient rule: the derivative of a quotient is:

[the denominator × the derivative of the numerator less the numerator × the derivative of the denominator] / [denominator]²

(f/g)' = [ g×f' - f×g'] / g²

So,

tan(x)' = [ sin(x) / cos(x)]'

[ sin(x) / cos(x)]' = [ cos(x) sin(x)' - sin(x) cos(x)' ] / [cos(x)]²

= [ cos(x)cos(x) + sin(x) sin(x) ] / [ cos(x)]²

= [ cos²(x) + sin²(x) ] / cos²(x)

= 1 / cos² (x)

= sec² (x)

The result is that the derivative of tan(x) is sec² (x)

4 0

3 years ago

Calcium hydroxide is a strong base but is not very soluble ( Ksp = 5.02 X 10-6 ). What is the pH of a saturated solution of Ca(O

Misha Larkins [42]

Answer : The pH of a saturated solution is, 12.33

Explanation : Given,

$K_{sp}$ = $5.02\times 10^{-6}$

First we have to calculate the solubility of $OH^-$ ion.

The balanced equilibrium reaction will be:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

Let the solubility will be, 's'.

The concentration of $Ca^{2+}$ ion = s

The concentration of $OH^-$ ion = 2s

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ca^{2+}][OH^-]^2$

Let the solubility will be, 's'

$K_{sp}=(s)\times (2s)^2$

$K_{sp}=(4s)^3$

Now put the value of $K_[sp}$ in this expression, we get the solubility.

$5.02\times 10^{-6}=(4s)^3$

$s=1.079\times 10^{-2}M$

The concentration of $Ca^{2+}$ ion = s = $1.079\times 10^{-2}M$

The concentration of $OH^-$ ion = 2s = $2\times (1.079\times 10^{-2}M)=2.158\times 10^{-2}M$

First we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (2.158\times 10^{-2})$

$pOH=1.67$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1.67=12.33$

Therefore, the pH of a saturated solution is, 12.33

7 0

3 years ago

The state of matter represented on the right (letter D) has the

jek_recluse [69]

Answer:

A is the answer.

Explanation:

gorgeousness

5 0

3 years ago

Which of the following is an example of an experimental scientific investigation

sleet_krkn [62]

Scientific investigation is the process in which scientist solve the problems by using different systematic approach. It can be initiated in different ways.

Experimental Scientific investigation: The investigation in which scientist answer the question on the basis of experimental results. Experimental investigation contains both dependent and independent variables, and only one variable is tested at a time is possible. This process makes uses of collecting observation and identifying the process in physical word.

Noting the colour of a solution when heated is the experimental scientific investigation

Therefore, other given options are part of scientific observation whereas Noting the colour of a solution when heated explains the experimental scientific investigation.

7 0

3 years ago

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