I think the correct answer from the choices listed above is the first option. The element that has the highest standard reduction potential would be fluorine. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
V₂ = 72.2 mL
Explanation:
Given data:
Initial volume = 146.0 mL
Initial pressure = 1.30 atm
Initial temperature = 5.00 °C (5.00 +273 = 278 K)
Final temperature = 2.00 °C ( 2.00+273 = 275 K)
Final volume = ?
Final pressure = 2.60 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂ /T₁P₂
V₂ = 1.30 atm × 146.0 mL × 275 K / 278K × 2.60 atm
V₂ = 52195 atm .mL. K / 722.8 K.atm
V₂ = 72.2 mL
Mole percent is the percentage of the total moles that is of a particular component.
One atom is a metal and one is a nonmetal.
One atom has high electronegativity value, while the other value is really low
