When a 1:1 mixture of ethyl butanoate and ethyl acetate is treated with sodium ethoxide, four Claisen condensation products are
possible.
-Draw the structure(s) of the product(s) that have an ethyl group on the chiral center.
-Although chirality may be mentioned in the question, do not include chirality in your drawings. .
-Do not draw organic or inorganic by-products .
-Draw one structure per sketcher. Add additional sketchers using the dropdown menu in the bottom right corner. .
-Separate multiple products using the +sign from the dropdown menu
-Draw the structure(s) of the product(s) that have an ethyl group on the chiral center.
-Although chirality may be mentioned in the question, do not include chirality in your drawings. .
-Do not draw organic or inorganic by-products .
-Draw one structure per sketcher. Add additional sketchers using the dropdown menu in the bottom right corner. .
-Separate multiple products using the +sign from the dropdown menu
1 answer:
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Answer:
(2R,3S)-2-ethoxy-3-methylpentane
and
(2S,3S)-2-ethoxy-3-methylpentane
Explanation:
For this case, we will have as nucleophile. Also, this compound is also in excess. So, we will have as solvent
a protic solvent. Therefore the Sn1 reaction would be favored.
The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)
Formula:
Solving:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)
Formula:
Solving:
<u>Answer:</u> The correct option is d) 460 kJ
<u>Explanation:</u>
We are given:
Content of fat in energy drink = 2.0 g
Content of protein in energy drink = 6.0 g
Content of carbohydrate in energy drink = 16.3 g
Also,
The fuel value of fat = 38 kJ/g
The fuel value of protein = 17 kJ/g
The fuel value of carbohydrate = 17 kJ/g
So, the fuel value of the energy drink will be:
Total fuel value =
Total fuel value =
Hence, the correct option is d) 460 kJ