Question

Michael wrote all the number s from 3 to (n+5). How many numbers did Michael write.

Answer 1

Answer:

$n-1$

Step-by-step explanation:

The amount of integers between $a$ and $b$ inclusive is always $|a-b|-1$.

This means the amount of integers Michael wrote is $|(3)-(n+5)|-1=|-2-n|-1=|n+2|-1$. Because $n+5>=3$ , which gives $n>=-2$, $n+2$ is always non-negative. So, we can kick out the absolute value sign to get $n+2-1=n-1$.

So, he wrote $\boxed{n-1}$ integers and we're done!