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maxonik [38]
3 years ago
6

Select the expression that is equivalent to (x-3)^2

Mathematics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

B.

{ \tt{ {(x - 3)}^{2} }} \\  \\  = { \tt{(x - 3)(x - 3)}} \\  \\  = { \tt{ {x}^{2} - 6x + 9 }}

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Can anyone help please
Akimi4 [234]

Answer: X = 27

Step-by-step explanation: If we observe very closely, we have two similar triangles in the diagram. The first one is ABC and the other triangle is EDC. Also take note that angle ACB in the first triangle is equal in measurement to angle ECD (45 degrees) in the other triangle, (Opposite angles).

Hence in triangle ECD, we have identified two angles so far which are angle 2x + 10 and angle 45. Same applies to triangle ABC, we already have two angles which are, 3x - 10 and 45.

However angle D in the second triangle is equal in measurement to angle B in the first triangle

(Alternate angles).

Hence we have a third angle in triangle ABC which is

Angle B = 2x + 10.

Therefore 3x - 10 + (2x + 10) + 45 = 180

(Sum of angles in a triangle)

3x - 10 + 2x + 10 + 45 = 180

By collecting like terms we now have

3x + 2x = 180 + 10 - 10 - 45

5x = 135

Divide both sides by 5,

x = 27

8 0
3 years ago
Estimate the product of 204 times 0.46
nikdorinn [45]
204 times .46 equals 93.84, to round of it would be 93.8
3 0
3 years ago
Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)
Lorico [155]

Answer:

It is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x .

Step-by-step explanation:

We already have the identity of x as \sin ^{2}x + \cos ^{2}x = 1 .......... (1)  .

So, from equation (1) we can write that

\cos ^{2} x = 1 - \sin ^{2} x

⇒ 6\cos ^{2} x = 6 - 6 \sin ^{2} x

⇒ 6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3

⇒ 6\cos ^{2}x -3 = 3 - 6\sin ^{2} x

Hence, it is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x . (Answer)

5 0
4 years ago
A bag contains 12 red, 30 blue, 20 green, 10 yellow, and 8 black marbles. Nancy chooses 1 marble from the bag. What is the proba
saul85 [17]

Answer:

5/8

Step-by-step explanation:

12+30+20+10 +8 =80 total marbles

12+30+8=50 red blue and black

50/80

5/8

6 0
3 years ago
Which equation describes a line parallel<br> to y= 4x+ 5 through point (-2, 1)?
Tema [17]

Hi there!

For a line to be PARALLEL, it must contain the same slope.

The given line has a slope of 4, so we can use the point-slope formula to solve:

\large\boxed{y - y_1 = m(x - x_1)}

y1 = y-coordinate of given point

x1 = x-coordinate of given point

m = slope

Plug in the values:

y - 1 = 4(x - (-2))\\\\y - 1 = 4(x + 2)

Simplify:

y - 1 = 4x + 8\\\\\boxed{y = 4x + 9}

8 0
2 years ago
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