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maxonik [38]
2 years ago
6

Select the expression that is equivalent to (x-3)^2

Mathematics
1 answer:
Elan Coil [88]2 years ago
6 0

Answer:

B.

{ \tt{ {(x - 3)}^{2} }} \\  \\  = { \tt{(x - 3)(x - 3)}} \\  \\  = { \tt{ {x}^{2} - 6x + 9 }}

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Help please help me please​
madam [21]

Answer:

B

Step-by-step explanation:

Only 1 because

1/1 = 1

2/1 = 2

The answer can't be 0 because we can't divide by zero.

The answer can't be 2 because you can't divide 1 by 2 without having a number with decimal places

Same thing for the 4

6 0
2 years ago
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Choose all of the terms that describe the set of lines.
viktelen [127]

These lines are only parallel lines because these lines don't touch each other and parallel lines don't touch each other.

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3 years ago
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Ms. Lunette has 18 students in her class. She wants to send 3 of these students to pick up books for the class.
tigry1 [53]

The number of possible combinations is given by

... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations

_____

There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.

7 0
3 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0
3 years ago
Can measurment be used with gcf
Tcecarenko [31]
What does "gcf" stand for?
5 0
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