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3 years ago

Write the equation of the line that passes through the points (2,2) and (3,4)

Mathematics

1 answer:

Scrat [10]3 years ago

8 0

9514 1404 393

Answer:

y -2 = 2(x -2)

Step-by-step explanation:

The slope of the line is given by the slope formula:

m = (y2 -y1)/(x2 -x1)

m = (4 -2)/(3 -2) = 2/1 = 2

The point-slope form of the equation for the line is ...

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

For the first point and the slope we found, the equation is ...

y -2 = 2(x -2)

You can rearrange this to any form you may like.

y -2 = 2x -4 . . . eliminate parentheses

y = 2x -2 . . . . . slope-intercept form

2x -y = 2 . . . . . standard form

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2 years ago

(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll

goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is $(0,0),(1,1),(2,2) \ and \ (3,3)$

Thus, the reflexive closure: $R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}$

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is: $(0,1),(0,2)\ and \ (0,3)$

Thus, the Symmetrical closure:

$R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}$

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3 years ago

Need help asap i will help u if u help me

sammy [17]

Answer: (10,9) is the correct answer.

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