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Leokris [45]
3 years ago
9

Write the equation of the line that passes through the points (2,2) and (3,4)

Mathematics
1 answer:
Scrat [10]3 years ago
8 0

9514 1404 393

Answer:

  y -2 = 2(x -2)

Step-by-step explanation:

The slope of the line is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (4 -2)/(3 -2) = 2/1 = 2

The point-slope form of the equation for the line is ...

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

For the first point and the slope we found, the equation is ...

  y -2 = 2(x -2)

__

You can rearrange this to any form you may like.

  y -2 = 2x -4 . . . eliminate parentheses

  y = 2x -2 . . . . . slope-intercept form

  2x -y = 2 . . . . . standard form

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How i can answer this question, NO LINKS, if you answer correctly i will give u brainliest!
Helga [31]

Answer:

4:6 = 2:3, the answer is C

Step-by-step explanation:

they visited 4 museums as displayed on the bar and 6 beaches also presented on the bar, which would mean 4:6 and would simplify to 2:3

4 0
2 years ago
I need an explanation how to do this ASAP I will give you 20 POINTS!!
mars1129 [50]
For the first digit you are choosing from 2 digits
for the second digit you are choosing from 2 digits
for the third digit you are choosing from 2 digits
2*2*2=8
111
110
011
101
000
001
100
010
However......
A number doesn't usually start with a 0 or 0s.
Therefore, if you want 3-digit numbers and not just permutations using 0 and 1, then you must eliminate
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Seeing that the first digit can't be 0, you choose from 1, then 2, and then 2 digits again; 1*2*2=4 numbers
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6 0
3 years ago
Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

                              P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0

Thus,

                                    Q_x -P_y = 0 -2 = - 2

Now, by the Green's theorem, we have

\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x  \Big|_{-3}^{4} = -42

4 0
3 years ago
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zalisa [80]

Answer:

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cost of 1 orange = £0.48 ÷ 2 = £0.24

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